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2 years ago

............................hhh look at the picture

Chemistry

1 answer:

kifflom [539]2 years ago

5 0

Neon :

Number of proton = 10
Group 18

<h3>Further explanation</h3>

Given

Neon atom

Required

Number of proton

Group in periodic table

Solution

Atomic number of Neon : 10

Electron configuration : [He] 2s²2p⁶

Number of proton = atomic number = 10

Neon and Helium are in the same group which is group 18 (the noble gases)

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What makes gas turn into a liquid?

lesantik [10]

I would say compression or the absence of heat because heating a liquid makes it a gas<span />

3 0

3 years ago

Which substance is the oxidizing agent in the following reaction? Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Which substance

aleksandr82 [10.1K]

Answer:

HNO3 is the oxidizing agent

Explanation:

Step 1:

The oxidizing agent is responsible to oxidize another. but itself undergoes a reduction .

Fe2S3:

Fe has an oxidation number of +3

S has an oxidation number of -2

HNO3:

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

H has an oxidation number of +1

N has an oxidation number of +5

Fe(NO3)3

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

Fe has an oxidation number of +3

Since NO3 has an oxidation number of -1; N has an oxidation number of +5

S alone has an oxidation number of 0

NO2:

O has an oxidation number of -2 (we have 2 times O, this makes -4)

N has an oxidation number of +4

Fe doesn't change from oxidation number. It stays +3

N goes from +5 to +4 → this is a reduction

S goes from -2 to 0 → this is an oxidation

The reducing agent is the compound that contributes the oxidized species (S).

The oxidizing agent contributes the reducing species (N)

The answer is HNO3

5 0

3 years ago

How much heat is released when 75 g of octane is burned completely if the enthalpy of combustion is -5,500 kJ/mol CsH18? C8H18 +

aalyn [17]

Answer : The correct option is, (D) 3600 kJ

Explanation :

Mass of octane = 75 g

Molar mass of octane = 114.23 g/mole

Enthalpy of combustion = -5500 kJ/mol

First we have to calculate the moles of octane.

$\text{ Moles of octane}=\frac{\text{ Mass of octane}}{\text{ Molar mass of octane}}=\frac{75g}{114.23g/mole}=0.656moles$

Now we have to calculate the heat released in the reaction.

As, 1 mole of octane released heat = -5500 kJ

So, 0.656 mole of octane released heat = 0.656 × (-5500 kJ)

= -3608 kJ

≈ -3600 kJ

Therefore, the heat released in the reaction is 3600 kJ

5 0

2 years ago

Determine which physical conditions are necessary to support nuclear fusion and formation of stars.

Ilia_Sergeevich [38]

Answer:

Promotes Stellar Formation:

-Increased Gravitational Attraction

-Higher Temperature

Does Not Promote Stellar Formation:

-Decreased Gravitational Attraction

-Lower Temperature

Explanation:

Stars need at least three million kelvins to form, and the gravitational attraction helps form the star in the first place.

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2 years ago

BRAINLIESTTT ASAP!!! PLEASE HELP ME :))

garri49 [273]

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Given: [1 gram = 0.04 ounce, 1 liter = 1,000 milliliter]

1.25 x 0.04 = 0.05 oz

Therefore, 0.05 per 1,000 milliliter

0.05 ÷ 1,000 = 0.00005 oz

Therefore, the density of the gas is 0.00005 oz/mL

Hope this helps! :)

6 0

3 years ago