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2 years ago

............................hhh look at the picture

Chemistry

1 answer:

kifflom [539]2 years ago

5 0

Neon :

Number of proton = 10
Group 18

<h3>Further explanation</h3>

Given

Neon atom

Required

Number of proton

Group in periodic table

Solution

Atomic number of Neon : 10

Electron configuration : [He] 2s²2p⁶

Number of proton = atomic number = 10

Neon and Helium are in the same group which is group 18 (the noble gases)

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Write the number 874.591 correct to 2 decimal places<br>

alisha [4.7K]

Answer:

874.59

Explanation:

The number after 9 is 1

1 is lower than 5 so we leave the previous number the same

3 0

3 years ago

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For each of the following substances below, identify the type of bonding between the atoms. Justify your

solniwko [45]

Answer:

SF4 -Covalent bond

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Explanation:

Sulphur and fluorine are non metals. Nonmetal atoms combine by the sharing of electrons. This is also called a covalent combination(bond).

In BaBr2, a metal is combined with a nonmetal. This combination involves a transfer of electrons from the metal to the nonmetal forming an ion pair. This is otherwise called an ionic bond.

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2 years ago

Theoretically how many moles of carbonic acid will be produced by the 3.00 g sample of NaHCO3

yaroslaw [1]

NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol
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3 years ago

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givi [52]

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8 0

3 years ago

Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o

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Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

6 0

3 years ago