Answer:
A) 3.868x10^26 W
B) 8176.678 K
C) 3.544x10^-7 m
D) 393.187 K
Explanation:
Detailed explanation and calculation is shown in the image below.
Answer:
Hello your question is incomplete attached below is the complete question
answer: wt.% of alloy that is solid = 61.5%
wt.% of allot that is liquid = 38.5%
Explanation:
To determine the wt.% of the alloy that is solid
= 
=
= 61.5%
To determine the wt.% of the alloy that is liquid
= 
=
= 38.5%
attached below is a free hand sketch as well
Here is the flow sheet. Hope this helps have a great day!!
Answer:
you never mentioned the options
Answer:288 pm
Explanation:
Number of atoms(s) for face centered unit cell -
Lattice points: at corners and face centers of unit cell.
For face centered cubic (FCC), z=4.
- whereas
For an FCC lattices √2a =4r =2d
Therefore d = a/√2a = 408pm/√2a= 288pm
I think with this step by step procedure the, the answer was clearly stated.