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Oksi-84 [34.3K]
3 years ago
6

(,,)=^3−^3+^3, where is the sphere ^2 + ^2 + ^2=^

Engineering
1 answer:
miv72 [106K]3 years ago
7 0
I have no clue hahahaha
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Two common types of glue
dolphi86 [110]

Answer:

white craft glue

yellow wood glue

Explanation:

the answer is this!

was it correct?sir!?

8 0
2 years ago
Read 2 more answers
You are given a rectangular piece of cloth with dimensions X by Y, where X and Y are positive integers, and a list of n products
Bond [772]

The proof that recursion is exponential and that dynamic programming is polynomial is given by the formula;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

To prove that the recursion is exponential and that dynamic programming is polynomial. we will do so as follows;

Let us first have the assumption that the cloth is in such a manner that  either way, a product can be oriented. This implies that that after a cut, we will now have two pieces of cloth.

Now, we will make a list of the side lengths of the products that can fit in the piece after which we will consider a vertical cut for each of the side length as well as a horizontal cut for each of the side length, then we apply the same algorithm to each of the two resulting pieces.  

Thus, after the point above, it is likely true that in some instances, there may be a place to cut that is not at a product side length. However, It might be better for us to make a list of lengths composed of one or more pieces side by side as long as the sum is less than the length of the side being considered.

 

Lastly, we would note that this recursive approach is not limited to just two -dimensional problems as It could also be applied to a single or more than two dimensions. A useful proof would be to prove it for one dimension, then assuming it is true for n dimensions, prove it is true for n + 1 dimensions.

Thus;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

Read more at; brainly.com/question/11665190

3 0
2 years ago
A closed, 0.4-m-diameter cylindrical tank is completely filled with oil (SG 0.9)and rotates about its vertical longitudinal axis
egoroff_w [7]

Answer: p_{B} - p_{A} = 28800 Pa or 28.8 kPa

Explanation: To determine the pressure of a liquid in a rotating tank,it is used:

p = \frac{p_{fluid}.w^{2}.r^{2} }{2} - γfluid . z + c

where:

p_{fluid} is the liquid's density

w is the angular velocity

r is the radius

γfluid.z is the pressure variation due to centrifugal force.

For this question, the difference between a point on the circumference and a point on the axis will be:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}.r_{B} ^{2} }{2} - γfluid.z_{B} - (\frac{p_{fluid}.w^{2}.r_{A} ^{2} }{2} - γfluid.z_{A})

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} ) - γfluid(z_{B} -z_{A})

Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} )

p_{B} - p_{A} = \frac{0.9.10^3.40^2}{2}(0.2^2 - 0)

p_{B} - p_{A} = 28800

The difference in pressure between two points, one on the circumference and the other on the axis is p_{B} - p_{A} = 28800 Pa or 28.8 kPa

8 0
3 years ago
Elliot wants to show a spherical radius in a technical drawing. Where should he place the symbol “SR” in the drawing?
gogolik [260]
I think it’s ( C with a leader line
4 0
3 years ago
What is a dynamic load? *
alexira [117]
Answer: Bricks in Building
8 0
3 years ago
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