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3 years ago

10

The pull of what is weaker when 2 objects are farther apart

1 answer:

9966 [12]3 years ago

7 0

The gravitational pull is weaker.

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What substances were found in the innermost regions (within about the inner 0.3 AUAU) of the solar system before planets began t

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Answer:

Hydrogen and helium compounds.

Explanation:

We know that the solar System was formed around <u>4.6 billion years ago, </u>due to the gravitational collapse of a giant interstellar molecular cloud.

This cloud is a type of interstellar cloud and its density and size permit the formation of molecules, most commonly molecular hydrogen.

Therefore the principal substances were found before planets began to form are hydrogen and helium compounds, besides Rocks, metals, most of them in gaseous form.

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3 years ago

An adult with a BMI of 25 to 30 is considered

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Option A overweight

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2 years ago

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All of the following affect the climate of an area except

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C. A cold front that came through does not affect the climate of an area.

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A boy weighs 50 kg and is running with 225 J of energy, what is his velocity?

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0.22

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3 years ago

Read 2 more answers

dybincka [34]

Answer:

1. 218.55 N

2. $30.96^{o}$

3. $2.1 m/s^{2}$

Explanation:

Part 1;

Net force $F=mg sin \theta$ where m is mass, g is gravitational force and $\theta$ is the angle of inclination

$F= 46*9.8*sin 29^{o}= 218.55N$

Frictional force, $F_{r}$ is given by

$F_{r} = \mu_{s}mg cos \theta$ where $\mu_{s}$ is the coefficient of static friction

$F_{r} = 0.6*46*9.8 cos 29$

$F_{r}=236.57N$

Since $F_{r}>F$ , therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force $F_{s} = \mu_{s} mg cos \theta$

$mg sin \theta =\mu_{s} mg cos \theta$

$\mu_{s}= \frac {sin \theta}{cos \theta}$

$\mu_{s}= tan \theta$

The maximum angle of inclination $\theta = tan^{-1} \mu_{s}$

$\theta = tan^{-1} (0.6)$

$\theta= 30.96^{o}$

Part 3:

Net force on the object is given by

$ma = mg sin 38 - \mu_{k} mg cos 38$ where $\mu_{k}$ is the coefficient of kinetic friction

$a = g ( sin 38 - \mu_{k} cos 38 )$

= 9.8 ( sin 38 - (0.51) cos 38 )

= $2.1m/s^{2}$

7 0

3 years ago