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Serggg [28]
3 years ago
12

A grandfather clock is "losing" time because its pendulum moves too slowly. Assume that the pendulum is a massive bob at the end

of a string.
The motion of this pendulum can be sped up by:

a) decreasing the mass of the bob.
b) increasing the mass of the bob.
c) lengthening the string.
d) shortening the string.
Physics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

The motion of this pendulum can be sped up by shortening the string. <em>(d)</em>

IgorC [24]3 years ago
5 0

Answer:

d) shortening the string

Explanation:

Time period of a pendulum clock is dependent on two factors namely:length and acceleration due to gravity.

When a clock loses time, the time period of the pendulum clock increases.

This however can be corrected by decreasing the length of the pendulum.The time period of the pendulum clock is not dependent on the mass of the bob. The time period of the pendulum clock can be corrected only by changing the length of the pendulum string.

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He chart below compares the characteristics of four objects, A, B, C, and D, discovered in the solar system.
Leto [7]

Answer:

Object A and C (Second choice)

Let's observe one by one

#A..

Kupier belt is a belt associated at Neptune outerside similar to asteroid belt

  • Hence it's correct

#B.

Has enough gravity to keep other objects far away from its orbit

  • It's any planet or may be sun /star

No

#C

Is in orbit around the sun

  • Sure it's correct

#D

Is almost circular in shape

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5 0
2 years ago
Your friend says that the force that the sun exerts on earth is much larger than the force that earth exerts on the sun. part a
Verizon [17]
I disagree with that opinion, and I have solid Physics to back me up.

The forces of gravity are always equal in both directions. The sun pulls the Earth with exactly the same force with which the Earth pulls the sun.

It may seem weird, but your weight on Earth is exactly the same as the Earth's weight on you. For the same reason.
8 0
3 years ago
Read 2 more answers
The flow control circuit design that can best control an overrunning load is the ____ circuit.
lara31 [8.8K]

The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.

The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.

  • The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.

Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

Learn more about Circuit here:

brainly.com/question/26064065

#SPJ4

3 0
2 years ago
Match the term to the correct description.
stiks02 [169]
1. Resistor
2. Insulator
3. Current
4. Semiconductor
5. Conductor
4 0
3 years ago
Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t
alexandr1967 [171]

Answer:

a) the one with a lower orbit    b) the one with a higher  orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

\frac{v^2}{r} = \frac{GM}{r^2}.

so the velocity is

v = \sqrt{\frac{GM}{r} }

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

T = 2\pi \sqrt{\frac{a^3}{GM} }

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0
3 years ago
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