When unpolarized light is incident on a sheet of polarizing material with a transmission axis oriented vertically, what percenta
1 answer:
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Answer:
65.9°
Explanation:
When light goes through air to glass
angle of incidence, i = 35°
refractive index, n = 1.5
Let r be the angle of refraction
Use Snell's law
Sin r = 0.382
r = 22.5°
Now the ray is incident on the glass surface.
A = r + r'
Where, r' be the angle of incidence at other surface
r' = 60° - 22.5° = 37.5°
Now use Snell's law at other surface
Where, i' be the angle at which the light exit from other surface.
Sin i' = 0.913
i' = 65.9°
Answer:
(a) Ey is negative
(b) The magnitude of the electric field is E = 171.429 V/m
(c) The potential difference between points B and C is 17.1429 V
Explanation:
(a) Here, we have the potentials given by;
with point A at y = 8.00 cm and point B at point y = 15.0 cm
where point B is at a higher potential than point A, that is the electric potential is from;
B with y = 15.0 cm to A with y = 8.0 cm which means
decreases as y increases or
is negative.
(b) The magnitude of the electric field is given by
The work done to move a charge from B to A is
where
∴
E = 171.429 V/m
(c) Here we have point C x = 5.00 cm and y = 5.00 cm
Therefore we have the distance from B to C given by
Where 10.00 cm = 0.01 m
E = V/Δy
Therefore, V = Δy·E
For , Δy =
and we have,