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Phoenix [80]
3 years ago
15

Be sure to answer all parts. Which product(s) form(s) at each electrode in the aqueous electrolysis of the following salts? Sele

ct as many as apply. (a) FeI2 Cathode: Anode: I− (aq) I2 (s) Fe (s) Fe2+ (aq) I− (aq) I2 (s) Fe (s) Fe2+ (aq) (b) K3PO4 Cathode: Anode: O2 (g) H2 (g) H+ (aq) OH− (aq) O2 (g) H2 (g) H+ (aq) OH− (aq)
Chemistry
1 answer:
zlopas [31]3 years ago
4 0

Answer:

FeI2

Anode

Fe^2+

Cathode

I2

K3PO4

Anode

H^+ and K^+

Cathode

H2

Explanation:

In electrolysis, there are two electrodes present, the cathode and the anode. The anode is the positive electrode. This is where oxidation occurs and positive ions are formed. Species give up a electrons at the anode and the electrons travel towards the cathode.

At the cathode (negative electrode where reduction occurs), species accept electrons according to their position in the electrochemical series. In the case of K3PO4, both hydrogen and potassium ions arrive at the cathode but hydrogen in preferentially discharged due to the position of the two ions in the electrochemical series.

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Use molecular orbital theory to determine whether He2 2+ or He2 + is more stable. Use molecular orbital theory to determine whet
julia-pushkina [17]

Answer:

The He₂ 2+ ion is more stable since it has a higher bond order (bond order = 1) than the He₂ + ion (bond order = 1/2).

Explanation:

Molecular orbital of He₂⁺

1\sigma_{1s}^21\sigma(star)_{1s}^1

There are two electrons in bonding and 1 electron in antibonding orbital

Bond order = \frac{(2-1)}{2}    

= \frac{1}{2}

Molecular orbital of He₂⁺²

1\sigma_{1s}^21\sigma(star)_{1s}^0

There are two electrons in bonding and 0 electron in antibonding orbital

Bond order = \frac{(2-0)}{2}

= 1

So bond order of He₂⁺² is 1 which is more stable than He₂⁺ whose bond order is   \frac{1}{2}   .

7 0
3 years ago
The molar absorptivity of Beta-carotene at 490 nm is 1.36 x 105 M-1cm-1. What is the concentration of a solution of Beta-caroten
finlep [7]

Answer:

The correct answer to the following question will be Option E (1.0 x 10⁻³ M).

Explanation:

The given values are:

A\lambda =140

\varepsilon=1.36\times 10^5 \ M \ {cm^{-1}}

L = 1 \ cm

As we know,

⇒  A\lambda=\varepsilon CL

On putting the given values in the above formula, we get

⇒  140=1.36\times 10^5\times C\times 1

⇒  C=\frac{140}{1.36\times 10^5}

⇒  C=102.9\times 10^{-5} \ M

So that option E is the right answer.

3 0
3 years ago
How many helium atoms are there in a helium blimp containing 536 kg of helium? n = atoms?
Mariulka [41]

Answer:- 8.07*10^2^8atoms

Solution:- It is a unit conversion where it asks to convert kg of He to atoms. We need to convert kg to grams, grams to moles and finally moles to atoms.

We know that, 1 kg = 1000 g

Molar mass of He is 4.0 grams per mole and 1 mole of an atom equals to Avogadro number of atoms.

The set up would be as given below:

536kg(\frac{1000g}{1kg})(\frac{1mole}{4g})(\frac{6.02*10^2^3atoms}{1mole})

= 8.07*10^2^8atoms

So, there are 8.07*10^2^8atoms of He in it's 536 kg.



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