Be sure to answer all parts. Which product(s) form(s) at each electrode in the aqueous electrolysis of the following salts? Sele
ct as many as apply. (a) FeI2 Cathode: Anode: I− (aq) I2 (s) Fe (s) Fe2+ (aq) I− (aq) I2 (s) Fe (s) Fe2+ (aq) (b) K3PO4 Cathode: Anode: O2 (g) H2 (g) H+ (aq) OH− (aq) O2 (g) H2 (g) H+ (aq) OH− (aq)
In electrolysis, there are two electrodes present, the cathode and the anode. The anode is the positive electrode. This is where oxidation occurs and positive ions are formed. Species give up a electrons at the anode and the electrons travel towards the cathode.
At the cathode (negative electrode where reduction occurs), species accept electrons according to their position in the electrochemical series. In the case of K3PO4, both hydrogen and potassium ions arrive at the cathode but hydrogen in preferentially discharged due to the position of the two ions in the electrochemical series.
I believe the closest possible answer to this question are:Gas A effuses faster than gas B.The molar mass is directly proportional to the rate of effusion.Thank you for your question. Please don't hesitate to ask in Brainly your queries
