It is a sedentary rock. Limestone are usually affected by chemical weathering when rainwater (containing a weak carbonic acid) reacts with limestone. This causes the limestone to dissolve.
Answer:
A simple displacement reaction occurs when an iron nail is immersed to a beaker containing copper sulphate solution.
a)
Iron is more reactive than copper. As a result a displacement reaction will take place. The ferrous or Fe (II) irons will move to the solution. The copper ions (Cu II) will get deposited on the nail. This will cause the colour to change from blue to green.
b)
The equation can be written as:
Fe (s) + CuSO4 (aq) -> FeSO4 (aq) + Cu (s)
c)
A chemical change can be described as a change that causes a substance to change to another form. Hence, this reaction is a chemical change.
Answer:
The amount left after 49.2 years is 3mg.
Explanation:
Given data:
Half life of tritium = 12.3 years
Total mass pf tritium = 48.0 mg
Mass remain after 49.2 years = ?
Solution:
First of all we will calculate the number of half lives.
Number of half lives = T elapsed/ half life
Number of half lives = 49.2 years /12.3 years
Number of half lives = 4
Now we will calculate the amount left after 49.2 years.
At time zero 48.0 mg
At first half life = 48.0mg/2 = 24 mg
At second half life = 24mg/2 = 12 mg
At 3rd half life = 12 mg/2 = 6 mg
At 4th half life = 6mg/2 = 3mg
The amount left after 49.2 years is 3mg.
Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions
Answer:
0.83 g
Explanation:
Step 1: Write the balanced equation
Fe + CuSO₄ ⇒ Cu + FeSO₄
Step 2: Calculate the moles corresponding to 0.75 g of Fe
The molar mass of Fe is 55.85 g/mol.
Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe
The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.
Step 4: Calculate the mass corresponding to 0.013 moles of Cu
The molar mass of Cu is 63.55 g/mol.
