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The coefficients of the hydrocarbon and water is 61 and it is explained below.
Explanation:
We have to balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2. Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.
The unbalanced chemical equation is
C₈H₁₈ + O₂ → CO₂ + H₂O
To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by 8 to get 8 atoms of carbon on the products side.
C₈H₁₈ + O₂ → 8 CO₂ + H₂O
Now, we have 18 on the reactant side and 2 on the products side, so multiply the water molecule by 9 to get
C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O
8 * 2 atoms O + 9 *1 atoms O = 25 atoms O
By adding fractional coefficient to O₂ we get
C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O
Multiply all the coefficients by 2 we get,
2C₈H₁₈ + ( * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O
The balance equation is
2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
Add the coefficients to get their sum
= 2 +25 + 16 +18 = 61
Thus, The coefficients of the hydrocarbon and water is 61
Answer:
Explanation:
Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and for the reaction comes out to be negative.
Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and for the reaction comes out to be positive.
As the heat is absorbed the reactants , the reaction is endothermic and for the given endothermic reaction will be +127 KJ