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kiruha [24]
3 years ago
9

Chem help due in 2 hours. please help. problem 14.

Chemistry
1 answer:
Murljashka [212]3 years ago
6 0
14 )

a) 1 <span>HBr + 1 NaHCO</span>₃<span> = 1 CO</span>₂<span> + 1 H</span>₂<span>O + 1 NaBr

b) </span><span>2 HNO</span>₃<span> + 1 K</span>₂SO₃<span> = 1 H</span>₂<span>O + 2 KNO</span>₃<span> + 1 SO</span>₂

c) 2 HI<span> + 1 </span>Na₂S<span> = 1 </span>H₂S<span> + </span>2 <span>NaI

d) 1 </span><span>(NH</span>₄<span>)</span>₂<span>SO</span>₄<span> + 1 Ca(OH)</span>₂<span> = 1 CaSO</span>₄<span> + 2 H</span>₂<span>O + 2 NH</span>₃
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step 3:  <em>cancel the spectator  ions  in both side of equation ( ions which  do not take place in the reaction)</em>

<em> </em><em>    =</em> 2Cl^-  and  2H^+  ions

Step 4: <em>write the final net equation</em>

<em> Ba^2+(aq)  + SO4^2-(aq)→  BaSO4(s</em><em>)</em>

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