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3 years ago

Give the ΔH value for the decomposition of silver chloride as shown in the reaction 2AgCl(s)+127 kJ→2Ag(s)+Cl2(g).

Chemistry

1 answer:

choli [55]3 years ago

6 0

Answer: $\Delta H=+127kJ$

Explanation:

$2AgCl(s)+127kJ\rightarrow 2Ag(s)+Cl_2(g)$

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and $\Delta H$ for the reaction comes out to be positive.

As the heat is absorbed the reactants , the reaction is endothermic and $\Delta H$ for the given endothermic reaction will be +127 KJ

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WHEN I SAY I NEED HELP ASAP !!!

sweet [91]

Answer:

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3 years ago

Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Part A Calculate ΔG for this reaction at 25 ∘C under the following condit

kati45 [8]

Answer: The $\Delta G$ of the reaction at given temperature is -12.964 kJ/mol.

Explanation:

For the given chemical reaction:

$CH_3OH(g)\rightleftharpoons CO(g)+2H_2(g)$

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{CO})\times (p_{H_2}^2)}{p_{CH_3OH}}$

We are given:

$p_{CO}=0.140atm\\p_{H_2}=0.180atm\\p_{CH_3OH}=0.850atm$

Putting values in above equation, we get:

$K_p=\frac{(0.140)\times (0.180)^2}{0.850}\\\\K_p=5.34\times 10^{-3}$

To calculate the Gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 0 J (at equilibrium)

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = $5.34\times 10^{-3}$

Putting values in above equation, we get:

$\Delta G=0+(8.314J/K.mol\times 298K\times \ln(5.34\times 10^{-3}))\\\\\Delta G=-12963.96J/mol=-12.964kJ/mol$

Hence, the $\Delta G$ of the reaction at given temperature is -12.964 kJ/mol.

5 0

3 years ago

A gaseous mixture contains 443.0 Torr H 2 ( g ) , 369.9 Torr N 2 ( g ) , and 82.7 Torr Ar ( g ) . Calculate the mole fraction, χ

mr_godi [17]

Answer:

χH₂ = 0.4946

χN₂ = 0.4130

χAr = 0.0923

Explanation:

The total pressure of the mixture (P) is:

P = pH₂ + pN₂ + pAr

P = 443.0 Torr + 369.9 Torr + 82.7 Torr

P = 895.6 Torr

We can find the mole fraction of each gas (χ) using the following expression.

χi = pi / P

χH₂ = pH₂ / P = 443.0 Torr/895.6 Torr = 0.4946

χN₂ = pN₂ / P = 369.9 Torr/895.6 Torr = 0.4130

χAr = pAr / P = 82.7 Torr/895.6 Torr = 0.0923

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3 years ago

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8_murik_8 [283]

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3 years ago

Read 2 more answers

Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

Maksim231197 [3]

Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

1. Energy to heat the liquid water from 55ºC to 100ºC

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

$Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J$

2. Energy to change the liquid to steam at 100ºC

$L=\lambda \times n$

λ = 40.6kJ/mol

n = 10.1g / 18.015g/mol = 0.5606mol

$L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J$

3. Total energy

$1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ$

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3 years ago