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3 years ago

Which shows the conversion of 8.93 × 10-2 grams to milligrams?

Chemistry

1 answer:

Allushta [10]3 years ago

4 0

The prefix milli means thousand so the correct conversion factor is 1000mg/g

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What is the maximum amount of silver (in grams that can be plated out of 4.7 l of an agno3 solution containing 3.2 % ag by mass?

Alex

The maximum amount of silver will be all of that contained in the solution.
Silver in solution:
Solution volume = 4,700 ml
Solution mass = 1.01 x 4,700
Solution mass = 5170 g

Amount of silver = 5,170 x 0.032
Amount of silver = 165.44 grams

5 0

3 years ago

Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−]

Arlecino [84]

Answer:

A. 0.000128 M is the solubility of M(OH)2 in pure water.

B. $3.23\times 10^{-6} M$ is the solubility of $M(OH)_2$ in a 0.202 M solution of $M(NO_3)_2$ .

Explanation:

Solubility product of generic metal hydroxide = $K_{sp}=8.45\times 10^{-12}$

$M(OH)_2\rightleftharpoons M^{2+}+2OH^-$

S 2S

The expression of a solubility product is given by :

$K_{sp}=[M^{2+}][OH^-]^2$

$K_{sp}=S\times (2S)^2=4S^3$

$8.45\times 10^{-12}=4S^3$

Solving for S:

$S=0.000128 M$

0.000128 M is the solubility of M(OH)2 in pure water

Concentration of $M(NO_3)_2$ = 0.202 M

Solubility product of generic metal hydroxide = $K_{sp}=8.45\times 10^{-12}$

$M(OH)_2\rightleftharpoons M^{2+}+2OH^-$

S 2S

So, $[M^{2+}]=0.202 M+S$

The expression of a solubility product is given by :

$K_{sp}=[M^{2+}][OH^-]^2$

$8.45\times 10^{-12}=(0.202 M+S)(2S)^2$

Solving for S:

$S=3.23\times 10^{-6} M$

$3.23\times 10^{-6} M$ is the solubility of $M(OH)_2$ in a 0.202 M solution of $M(NO_3)_2$ .

8 0

4 years ago

Balance the following chemical equation (if necessary):

inessss [21]

Ca(C2H302)2(aq) + Na2CO3(aq) —> CaCO3(s) + 2 NaC2H302(aq)

7 0

3 years ago

If I have a 30,000 mL container that holds 65 moles of gas at a temperature of 205 degrees Celsius, what is the pressure inside

AnnyKZ [126]

Answer:

85.384 atm or 64608.13086 mmHg

Explanation:

PV= NRT

P= NRT/V

n= mols

R= gas constant (i used .0821 for atm)

T= Temp in Kelvins (Celsius degrees + 273)

V= in L

(65molsx480kx.0821)/30L

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3 years ago

A sample of a certain binary compound contains 6.93 g of silicon and 7.89 g of oxygen. What is the percent composition of the co

TiliK225 [7]

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3 years ago

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