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ra1l [238]
3 years ago
12

A 3.0-m wide rectangular asphalt channel discharges 33.84 m^3/s of water with a depth of 2.0 m. What is the head loss in 100 m l

ength of channel?
Engineering
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:

Head loss in 100 m length equals 1.00 m.

Explanation:

The head loss in an open channel is calculated using manning's equation as follows

Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}

For a asphalt rectangular channel we have

Area of flow = 3.0\times 2.0 = 6m^{2}

Wetted Perimeter = 3.0+2\times 2.0=7.0m

manning's roughness coefficient = 0.016

Applying values in the above equation we get

33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01

Now we know that

S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m

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A two-phase mixture of water and steam with a quality of 0.63 and T = 300F expands isothermally until only saturated vapor rema
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Answer:

Explanation:

Hello!

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through prior knowledge of two other properties.

3. Use temodynamic tables to find the density of water in state 1, by means of temperature and quality, with this value and volume we can find the mass.

3. Use thermodynamic tables to find the internal energy in state 1 and two using temperature and quality.

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2 years ago
The acceleration (in m/s^2) of a linear slider (undergoing rectilinear motion) within a If the machine can be expressed in terms
Inga [223]

Answer:

47.91 sec

Explanation:

it is given that \alpha =\frac{1}{4v^{2}}

at t=0 velocity =0 ( as it is given that it is starting from rest )

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we know that \alpha =\frac{dv}{dt}=\frac{1}{4v^{2}}

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at t=o it is given that v=0 putting these value in eqn 1 c=0

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3 years ago
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  • Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
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Explanation:

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