Answer: freezing and evaporation for sure
Explanation:
Answer:
Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.
What are the first two quantum numbers for the six electrons in the 2p subshell?
Explanation:
The principal quantum number represents the shell number in which the electron is present.
It is represented with "n".
The next quantum number is the azimuthal quantum number.
It represents the shape of the orbital.
It has values from 0 to (n-1).
Its value depends on the principal quantum number.
Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.
For the six elecetrons in 2p subshell:
The first two quantum number values are the same and their values are:
n=2 , l=1.
6+2=115 and its good it took test
Answer : The correct option is "record 10.00 ml in the notebook after using it."
Explanation :
If an instrument has "10 mL TD" written on it, that means the instrument is meant To Deliver (TD) 10 mL of volume.
Therefore the option that has 5.00 mL is not correct.
"+/- 0.01 mL" indicates the precision of the instrument. We know that no measurement is 100% accurate and there is always some uncertainty associated with any measurement.
Here, 0.01 indicates the uncertainty in the measurement.
When we have 0.01 mL , that means the instrument can record precisely to the hundredths place.
The more the significant figures, the greater is the accuracy of the measurement.
Therefore when we use an instrument that has "+/- 0.01 mL" written on it, we should record the reading as 10.00 mL
Answer:
21.4 L
Explanation:
Given data:
Volume of carbon dioxide produced = ?
Volume of oxygen = 37.4 L
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
It is known that,
1 mole = 22.414 L
There are 7 moles of oxygen = 7×22.414 = 156.9 L
There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L
Now we will compare:
O₂ : CO₂
156.9 : 89.66
37.4 : 89.66/156.9×37.4 = 21.4 L
So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.
