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almond37 [142]
3 years ago
9

What would be the empirical formula of a compound that is 25.5% carbon, 6.40% hydrogen, and 68.1% oxygen?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
Empirical formula is the simplest ratio of whole numbers of components in a compound 
in 100 g of compound 
                                C                          H                          O
mass                   25.5 g                     6.40 g                 68.1 g
number of moles  25.5 g/12 g/mol      6.40 g/ 1 g/mol      68.1 g/ 16 g/mol 
                             = 2.13 mol              = 6.40 mol          = 4.26 mol
divide by least number of moles 
                             2.13/2.13 = 1          6.40/2.13 = 3.0    4.26/2.13 = 2.0
all rounded off 
C - 1
H - 3
O - 2

empirical formula - CH₃O₂
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Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the
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Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

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From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

  • Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.
  • Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.
  • Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position
  • Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.
  • Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

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