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inn [45]
3 years ago
7

Which of the following is a property of water? It can freeze very fast. It has low heat capacity. It exists in all three states

on Earth. It repels other water molecules.
Chemistry
2 answers:
Mariana [72]3 years ago
7 0

It exists in three states .

ycow [4]3 years ago
6 0

Answer: It exists in all three states on earth.

Explanation:

Water is a tasteless, colorless and odourless liquid. On earth it exists in three states namely solid, liquid and gas.

Water as solid: The water in solid state exists as ice. Ice is frozen water. The molecules of water remains separate in ice. It exists in the glaciers or snow in some cold regions.

Water as liquid: The water in the liquid form is the most common form exists on earth. It is in the fluid form of water. It can be seen in the form of river, lakes, ponds, and oceans.

Water as gas: Water when heated it converts into gas. The gaseous form of water is called as water vapor. The water vapors remain in the earth atmosphere responsible for causing rain.

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Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

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