Pretty sure it’s ,B. Microscope!
Answer:
The endpoint volume is 50.52 ± 0.14 mL
Explanation:
In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:
V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)
V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL
V = 50.52 ± 0.14 mL
It is necessary to consider the sum of the errors too.
The charge for this compound is positive. For Fe, it's charge is positive 3, and for OH, it's charge is negative 1. You would then criss cross the charges of each and come out with Fe(OH)3. I hope this helped!! :)
Answer:
<em>This type of error affects overall accuracy but does not necessarily affect precision.</em> - Systematic error
<em>This type of error affects precision but does not necessarily affect overall accuracy.</em> - Random error
<em>This type of error occurs if you use a buret that was calibrated incorrectly when it was made.</em> - Systematic error
<em>You can minimize this type of error by taking repeated measurements.</em> - Random error
Explanation:
<em>Systematic errors are errors that are attributable to instrument being used during measurement or consistent incorrect measurement during a research</em>. They are consistently and repeatedly committed during measurements and therefore affect the overall accuracy of measurements. A person committing systematic error can have precise repeated measurement but will be far from being accurate.
R<em>andom errors on the other hand has no pattern and are usually unavoidable because they cannot be predicted.</em> When sufficient replicate measurements are made, such errors are reduced to the barest minimum and usually do not affect the overall accuracy of measurements.