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Anika [276]
3 years ago
5

Which of the following is the correct factored form of the given equation?

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

4x^2 - 11x + 6 = 0\\ 4x^2-8x-3x+6=0\\ 4x(x-2)-3(x-2)=0\\ (4x-3)(x-2)=0

Slav-nsk [51]3 years ago
4 0

Answer:  The correct option is (C) (4x-3)(x-2)=0.

Step-by-step explanation:  We are given to select the correct factored form of the following quadratic equation.

4x^2-11x+6=0

To do so, we need to factorize the left hand side of the above equation.

We have

4x^2-11x+6=0\\\\\Rightarrow 4x^2-8x-3x+6=0\\\\\Rightarrow 4x(x-2)-3(x-2)=0\\\\\Rightarrow (4x-3)(x-2)=0.

Therefore, the correct factored form of the given equation is

(4x-3)(x-2)=0.

Thus, (C) is the correct option.

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2 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)
Usimov [2.4K]

Answer:

<em>71.6 degrees </em>

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

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|v| = √81+81

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cos theta = 36/113.84

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

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