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VashaNatasha [74]
3 years ago
12

Calculate the volume of a gas at a pressure of 150 kpa if its volume at 180 kpa is 1500 L

Chemistry
1 answer:
Anastaziya [24]3 years ago
8 0

Answer: 1800 L

Explanation:

Given that,

Original pressure of gas (P1) = 180 kPa

Original volume of gas (V1) = 1500 L

New pressure of gas (P2) = 150 kPa

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P1V2

180 kPa x 1500 L = 150 kPa x V2

270000 kPa•L = 150 kPa•V2

Divide both sides by 150 kPa

270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa

1800L = V2

Thus, the new volume of the gas is 1800 liters.

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Answer:

5.195 ml

Explanation:

Dissociation of HCl yields;

HCl(aq)   ⇄   H⁺(aq)     +    Cl⁻(aq)

∴ [HCl] = [H⁺] = [Cl⁻]

pH = 1.9

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= 0.01258 × 4.80 L

= 0.06042 mole

Mass of HCl = number of moles of HCl  ×  Molar mass of HCl

Mass of HCl = 0.06042 mol ×  36.5 g/mol

Mass of HCl = 2.205 grams

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Mass of HCl in the solution = 36% of the density

i.e \frac{36}{100}*1.179

= 0.4244 grams

Volume of a concentrated HCl solution needed can now be determined as;

= \frac{2.205}{0.4244}

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What is the total number of molecules of hydrogen in 0.75 mole of hydrogen?
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Avogadro's number, 6.022 * 1023 is the number of things in one mole. The question indicates that there is 1 mole of H2. Thus there are 6.022 * 1023 molecules of H2

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