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Penn State Civil and Environmental Engineering Department just built a super-duper coal-fired power plant in Altoona, PA. It is

Travka [436]

Answer:

Part -A:

Sulfur released is $1.338 \times 10^{4}pounds/hour$ .

Part-B:

$SO_{2}$ released of per EPA norms is $4.865 /times 10^{-3}P/kw$ .

Explanation:

From the given,

The output = 1100 Mw

Efficiency = η = 0.4

Substitute the values in the following

Input = Output / η

$= \frac{1100}{0.4}= 2750 Mw$

Let's converts between joules to BTU.

1 BTU = 1056 J

Part-A;

$Energy\,\, required = Power \times time$

$2750 \times 10^{6} \,\, J/s \times 3600s = 9.9 \times 10^{12}J$

$Energy \,\, required = \frac{9.9 \times 10^{22}}{1056}= 9.375 \times 10^{9} BTU$

$Mass\,of\, coal\,required = \frac{9.375 \times 10^{9}}{14,000}=6.69 \times 10^{5}pounds$

But it has 2% sulfur

The mass of sulfur released

$6.69 \times 10^{5}pounds \,coal \times 0.02 = 1.338 \times 10^{4}pound$

Therefore, released sulfur is $1.338 \times 10^{4}pounds/hour$ .

Part -B;

One pound of sulfur produce two pounds of sulfur dioxide

Initial amount of produced sulfur =

$2 \times 1.338 \times 10^{4}pound = 2.676\times 10^{4}pound/hour$

Assuming we added a 80% efficiency then,

Released sulfur dioxide = $(1-0.8) \times SO_{2} \,produced =0.2 \times 2.676 \times 10^{4}Pounds/hr= 5.352 \times 10^{3}Pounds/hr$

Energy produced in an hour = $400 mw \times 1 hr = 1.1 \times 10^{6}kwh$

$SO_{2}\,released \, as \, per EPA = \frac{5.352 \times 10^{3} \,pounds}{1.1 \times 10^{6}kwh}= 4.865 \times 10^{-3}p\kwh$

Therefore, $SO_{2}$ released of per EPA norms is $4.865 /times 10^{-3}P/kw$ .

8 0

3 years ago

When sedimentary rock is exposed to heat and pressure,what does it change into?

SIZIF [17.4K]

Metamorphic rocks, because sedimentary rocks are formed from compressed sand, gravel, dirt, etc. and igneous rocks are formed by cooled magma, but of course each type of rock can be formed other ways. so it leaves us with metamorphic.

8 0

3 years ago

Select ALL! the solutes below that would be soluble in a polar solvent (like water).

Fofino [41]

Answer:

K2SO4, NH3, HOCI, HCI, CH3NH2, SiCl4, CO2, CH20

Explanation:

Substances are soluble in water when they are ionic or polar covalent substances.

If we look at the substances listed, K2SO4 is ionic while NH3, HOCI, HCI, CH3NH2, SiCl4, CO2, CH20 all contain polar covalent bonds which accounts for their water solubility.

Hence ionic and polar covalent substances are soluble in a polar solvent such as water.

6 0

3 years ago

The definition of oxidation is loss of electrons. The definition is formation of additional bonds between carbon and oxygen (or

Fynjy0 [20]

Answer:

Oxidation can be defined in many ways:

In terms of electron, Oxidation can be defined as loss of electrons by an atom or ion or a molecule during a reaction.

In terms of oxygen transfer, oxidation maybe defined as a substance that gains oxygen or loses hydrogen.

It can also be defined as a process in which a carbon atom gains bond to more electronegative atom such as oxygen.

8 0

3 years ago

What is the smallest unit of an element that retains the properties of that element?

Temka [501]

Answer:

Atom

Explanation:

The smallest unit which maintains an element's properties is an atom.

3 0

3 years ago

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