Question

A student took a calibrated 250.0 gram mass, weighed it on a laboratory balance, and found it read 266.5 g. What was the student’s percent error?​

Answer 1

Answer:

$\boxed{\text{6.60 \%}}$

Explanation:

$\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \,\%$

$\text{\% error} = \dfrac{\lvert 266.5 - 250.0\lvert}{250.0} \times 100 \, \% = \dfrac{\lvert 16.5\lvert}{250.0} \times 100 \, \% = \dfrac{16.5}{250.0} \times 100 \,\%\\\\ = 0.0660 \times 100 \, \% = \textbf{6.60 \%}\\\text{The student's percent error is \boxed{\textbf{6.60 \%}} }$