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Ilia_Sergeevich [38]
3 years ago
7

In electroplating, how should the object that will be plated be connected in the electrolytic cell?

Chemistry
1 answer:
blondinia [14]3 years ago
7 0

Answer:

c

Explanation:

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The answer is D Olive Oil

Due to water being a polar substance, and olive oil is a non-polar substance. They will not mix, the olive oil will sink to the bottom of the water and not dissolve.

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<h3>What is photon theory?</h3>

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Watch the animation and observe the titration process of a standard 0.100 M sodium hydroxide solution with 50.0 \rm ml of a 0.10
yuradex [85]

Answer:

Answers are in the explanation

Explanation:

a. The statments are:

The titration process is based on a chemical reaction.  <em>TRUE. </em>A titration is the chemical reaction between an acid and a base.

The pH of the solution at the equivalence point is 7.  <em>TRUE. </em>In a titration of strong acid with strong base the equivalence point is 7

At the endpoint, the pH of solution is 10 and the color of solution is pink.  <em>FALSE</em>. The endpoint in a strong acid - strong base titrationmust be near to equivalence point at pH = 7.

At the beginning of the titration process, the pH of the solution increases rapidly.  <em>FALSE. </em>At beginning of a titration, the pH of the solution increases slowly.

The chemical reaction involved in an acid-base titration is a neutralization reaction.  <em>TRUE. </em>In the reaction, you are neutralizing an acid (HCl) with a base (NaOH)

Before any base is added to the solution, the pH of the solution is high. <em>FALSE. </em>The addition of a base increases pH that is, in the beginning, low.

In a titration process, the endpoint is reached before the equivalence point.  <em>FALSE. </em>In a titration process, the endpoint is reached in the equivalence point

The pH of the solution changes very slowly at the equivalence point. <em>FALSE. </em>At the equivalence point, the pH changes rapidly.

b. For the reaction

NaOH + HCl → H₂O + NaCl

As the reaction is 1:1 and molarity of both solutions are the same, additions < 100mL of NaOH will stay before the equivalence point, equivalence point will be in 100mL and additions > 100mL of NaOH will stay after the equivalence point.

The conditions are:

10.0mL of 1.00 M NaOH before the equivalence point

150 mL of 1.00 M NaOH after the equivalence point

5.00 mL of 1.00 M NaOH before the equivalence point

50.0 mL of 1.00 M NaOH  before the equivalence point

200 mL of 1.00 M NaOH after the equivalence point

I hope it helps!

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hope this helps :)

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