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romanna [79]
3 years ago
6

Se necesita fuerza continua para el movimiento continuo?

Physics
1 answer:
zhenek [66]3 years ago
8 0

¿Se necesita fuerza continua para un movimiento continuo? No exactamente, ya que la fuerza que se aplica para mantener un objeto en movimiento solo se usa para que la fuerza de fricción pueda ser contrarrestada. Si un astronauta arrojara, digamos, una computadora portátil al espacio durante una caminata espacial (por qué arrojar una tableta perfectamente buena en el esquema interminable del cosmos, no lo sé), viajaría con una velocidad constante para siempre, a menos que golpea algo También podría reemplazar la computadora portátil con Voyager 2, que se mantuvo en movimiento y ahora está fuera de nuestro sistema solar. Esto se debe a que el espacio está mayormente vacío y no habría ninguna fuerza de fricción que actúe sobre esa roca. A menos que sea golpeado por un asteriodo o algo así, lo que haría una pregunta física diferente.

Espero que esto ayude, ¡TENGA UN DÍA BENDITO Y MARAVILLOSO! ¡Y un gran fin de semana de Superbowl! :-)

- Cutiepatutie ☺❀❤

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Answer:

Part a)

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Part b)

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Part c)

P = 540 watt

Part d)

P_r = 0.878

Explanation:

Part a)

As we know that the during the charging process of the battery the terminal voltage of the cell is given as

V = E + iR

V = 12 + (0.037)(45)

V = 13.665 V

Part b)

Thermal energy dissipated in the battery is due to its internal resistance

so it is given as

P = i^2 R

here we have

P = 45^2 (0.037)

P = 74.9 Watt

Part c)

rate of energy conversion in the in the battery is given as

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P = 12(45)

P = 540 watt

Part d)

percentage of the power conversion is given as

Pr = \frac{P_{out}}{P_{total}}

Pr = \frac{540}{540 + 74.9}

P_r = 0.878

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3 years ago
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Fynjy0 [20]

Answer:

C

Explanation:

7 0
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KiRa [710]

Answer:

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2 years ago
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3 years ago
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By Newton's second law, the net force on the object is

∑ <em>F</em> = <em>m</em> <em>a</em>

∑ <em>F</em> = (2.00 kg) (8 <em>i</em> + 6 <em>j</em> ) m/s^2 = (16.0 <em>i</em> + 12.0 <em>j</em> ) N

Let <em>f</em> be the unknown force. Then

∑ <em>F</em> = (30.0 <em>i</em> + 16 <em>j</em> ) N + (-12.0 <em>i</em> + 8.0 <em>j</em> ) N + <em>f</em>

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