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romanna [79]
3 years ago
6

Se necesita fuerza continua para el movimiento continuo?

Physics
1 answer:
zhenek [66]3 years ago
8 0

¿Se necesita fuerza continua para un movimiento continuo? No exactamente, ya que la fuerza que se aplica para mantener un objeto en movimiento solo se usa para que la fuerza de fricción pueda ser contrarrestada. Si un astronauta arrojara, digamos, una computadora portátil al espacio durante una caminata espacial (por qué arrojar una tableta perfectamente buena en el esquema interminable del cosmos, no lo sé), viajaría con una velocidad constante para siempre, a menos que golpea algo También podría reemplazar la computadora portátil con Voyager 2, que se mantuvo en movimiento y ahora está fuera de nuestro sistema solar. Esto se debe a que el espacio está mayormente vacío y no habría ninguna fuerza de fricción que actúe sobre esa roca. A menos que sea golpeado por un asteriodo o algo así, lo que haría una pregunta física diferente.

Espero que esto ayude, ¡TENGA UN DÍA BENDITO Y MARAVILLOSO! ¡Y un gran fin de semana de Superbowl! :-)

- Cutiepatutie ☺❀❤

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6. A car moving in a straight line at constant speed:
ddd [48]

Answer:

D. has no overall force acting on it.

Explanation:

Why?

Because in a straight line at the constant speed means the car moving in the same velocity, which is not acceleration neither deceleration, and it cannot be on a downhill slope. So the correct answer is

<h3>→ D. has no overall force acting on it.</h3>
8 0
3 years ago
If a body travels half its total path in the last 1.50 s of its fall from rest, find the total time of its fall (in seconds).
svetoff [14.1K]

Answer:

time to fall is 3.914 seconds

Explanation:

given data

half distance time = 1.50 s

to find out

find the total time of its fall

solution

we consider here s is total distance

so equation of motion for distance

s = ut + 0.5 × at²   .........1

here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time

so for last 1.5 sec distance is 0.5 of its distance so equation will be

0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)²     ........................1

and

velocity will be

v = u + at

so velocity v = 0+ 9.8(t-1.5)    ..................2

so first we find time

0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5)  + 0.5 ( 9.8)

solve and we get t

t = 3.37 s

so time to fall is 3.914 seconds

6 0
3 years ago
If you had an unlimited amount of mass to hang, what would be the range of possible accelerations for the system?
LenaWriter [7]

Answer:

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3 0
2 years ago
Two children, Ferdinand and Isabella, are playing with a water hose on a sunny summer day. Isabella is holding the hose in her h
mojhsa [17]

Answer:

Isabella will not be able to spray Ferdinand.

Explanation:

We'll begin by calculating the time taken for the water to get to the ground from the hose held at 1 m above the ground. This can be obtained as follow:

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.9

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s

Next, we shall determine the horizontal distance travelled by the water. This can be obtained as follow:

Horizontal velocity (u) = 3.5 m/s

Time (t) = 0.45 s

Horizontal distance (s) =?

s = ut

s = 3.5 × 0.45

s = 1.58 m

Finally, we shall compare the distance travelled by the water and the position to which Ferdinand is located to see if they are the same or not. This is illustrated below:

Ferdinand's position = 10 m

Distance travelled by the water = 1.58 m

From the above, we can see that the position of the water (i.e 1.58 m) and that of Ferdinand (i.e 10 m) are not the same. Thus, Isabella will not be able to spray Ferdinand.

8 0
3 years ago
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