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3 years ago

Why is gravity considered a force?

2 answers:

6 0

It is a force do to that way that it pulls objects down and a force is something that pushes or pulls an object so gravity is a force

sattari [20]3 years ago

5 0

Gravity is a force because it pulls down on objects.

You might be interested in

A long solenoid (diameter = 5.0 cm) is wound with 960 turns per meter of thin wire through which a current of 300 mA is maintain

Semenov [28]

Answer: The magnetic field B= 4.82×10^-4T

Explanation:

There are two sources of magnetic field; the magnetic field due to solenoid and magnetic field due to wire. Their sum will give the total magnetic field

The magnetic field due to solenoid is constant at any point while the magnetic field due to wire varies with 1/radius.

Since they are perpendicular to each other;

Using Pythagoras theorem

B^2 =(B1)^2+B2)^2

B1 is the magnetic field due to solenoid and B2 is the magnetic field due to wire

B1= (μNI1)/L

B2=μI2/2πr

Where N/L is the of turns per meter = 960m^-1

I1 is the current in the solenoid =300mA=0.3A

I2 is the current in the wire = 12A

r is the distance from the axis of solenoid = 2cm= 0.02m

μ is the magnetic constant= 4π×10^-7Tm/A

Magnetic field due to solenoid B1=(4π×10^-7×960×0.3)

B1= (3.6191×10^-4 )

Magnetic field due to wire

B2 = (4π×10^-7×12)/2π × 0.02

B2 = 1.2×10^-4

B^2 =( 3.16191×10^-4)^2 × (1.2×10^-4)^2

B=3.8×10^-4T

Therefore the magnetic field is 0.38mT

5 0

2 years ago

Light of wavelength 660 nm passes through two narrow slits 0.65 mm apart. The screen is 2.55 m away. A second source of unknown

stiv31 [10]

Answer:

Explanation:

Distance of 2 nd order fringe x₁ = 2 λ D/d [ λ is wave length , D is distance of screen , d is slit distance.

x₁ = 2 x 660 x10⁻⁹x 2.55/.65 x 10⁻³.= 5.17846 x 10⁻³ m.

Distance of fringe for 2nd radiation = 5.178 x 10⁻³ -1.17 x 10⁻³ = 4.008 x10⁻³

4.008 x 10⁻³ = 2 x λ x 2.55/.65 x 10⁻³

λ = 511 nm approx.

8 0

3 years ago

Anyone know the answer to this question?

nikitadnepr [17]

- The integers 1,2,3,4,5,6,7,8,9 are always significant

- Zeros in between numbers are always significant

Explanation:

The rules to determine whether a digit is significant or not are the following:

- All the non-zero digits are significant: 1,2,3,4,5,6,7,8,9

- The zeros between two non-zero numbers are always significant

- The zeros before non-zero numbers on the left of the decimal point are never significant

- The zeros given after a non-zero number on the right of the decimal point are significant if they provide information about the precision of the measure

So now let's analyze the statements given:

- The integers 1,2,3,4,5,6,7,8,9 are always significant --> true

- All numbers to the right of the decimal point are always significant --> false. For instance, in 0.012, only 1 and 2 are significant.

- Zeros to the left of a decimal point and in a number greater than or equal to 10 are always significant --> false. For instance, in 7200, the two zeros are not significant.

- All zeros are significant numbers --> false, as we saw in the previous examples

- Zeros in between numbers are alwasy significant --> true

Learn more about significant figures here:

brainly.com/question/5028090

#LearnwithBrainly

4 0

3 years ago

Jack and Jill exercise in a 25.0 m long swimming pool. Jack swims 9 lengths of the pool in 156.9 s ( 2 min and 36.9 s ) , wherea

Leya [2.2K]

Answer:

Jill average velocity is 0

Jack average velocity is 0.159337

Jill average speed = 1.593372

Jack average speed = 1.434034

Explanation:

given data

long swimming pool = 25.0 m

9 lengths of the pool = 156.9 s ( 2 min and 36.9 s )

10 lengths = same time interval

to find out

average velocity and average speed

solution

we know that average velocity that is express as

average velocity = $\frac{displacement}{time}$ .....................1

Jill come back where she start

so here velocity will be = 0

and

Jack ends up on the other end of pool

so average velocity = $\frac{25}{156.9}$

average velocity = 0.159337

now we get here average speed that is express as

average speed = $\frac{distance}{time}$ .............2

jack speed = 9 × $\frac{25}{156.9}$

jack speed = 1.434034

and

Jill speed = 10 × $\frac{25}{156.9}$

Jill speed = 1.593372

5 0

3 years ago

At what height from the surface of the earth does the value of acceleration due to gravity be 2.45 m/s square where the radius o

Citrus2011 [14]

Answer:

Explanation: RADIUS OF EARTH = 6400X1000m =

ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2

ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2

A/C TO FORmULA

g'/g=1-2h/Re

g'/g +2h/Re = 1

2h/Re =1- g'/g

2h= (1- g'/g)Re

2h=(1-2.45 /9.8)

6400X1000

2h = (0.75)6400X1000

2h = 4800000

h= 2400000

3 0

1 year ago