3.60 A = 3.60 coulombs of charge per second
(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge
1 coulomb of charge is carried by 6.25 x 10^18 electrons
Number of electrons =
(55.08 Coul) x (6.25 x 10^18 e/coul) = <em>3.4425 x 10^20 electrons</em>
Answer:
The value is 
Explanation:
From the question we are told that
The velocity is ![a = 120 \ km/h = [tex]\frac{120 * 1000}{3600} = 33.3 \ m/s](https://tex.z-dn.net/?f=a%20%3D%20%20120%20%5C%20%20km%2Fh%20%3D%20%20%5Btex%5D%5Cfrac%7B120%20%2A%20%201000%7D%7B3600%7D%20%3D%20%2033.3%20%5C%20%20m%2Fs)
[/tex]
The time taken is 
The time taken for contact is 
The velocity of the of the car after contact is ![v_c = 71.0 \ km/h = [tex]\frac{71 *1000}{3600} = 19.7 2 \ m/s](https://tex.z-dn.net/?f=v_c%20%3D%20%2071.0%20%5C%20%20km%2Fh%20%3D%20%5Btex%5D%5Cfrac%7B71%20%2A1000%7D%7B3600%7D%20%3D%20%2019.7%202%20%5C%20%20m%2Fs)
[/tex]
From the equation of kinematics we have that
Here u = 0 \ m/s since the car is initially motionless
=> 
=>
Answer:
B.convection currents in the mantle
Explanation:
Answer:
If freshwater consumption was greater than freshwater renewal.
Explanation:
Similar to another Brainly answer :O
Option(a) the mass of cart 2 is twice that of the mass of cart 1 is the right answer.
The mass of cart 2 is twice that of the mass of cart 1 is correct about the mass of cart 2.
Let's demonstrate the issue using variables:
Let,
m1=mass of cart 1
m2=mass of cart 2
v1 = velocity of cart 1 before collision
v2 = velocity of cart 2 before collision
v' = velocity of the carts after collision
Using the conservation of momentum for perfectly inelastic collisions:
m1v1 + m2v2 = (m1 + m2)v'
v2 = 0 because it is stationary
v' = 1/3*v1
m1v1 = (m1+m2)(1/3)(v1)
m1 = 1/3*m1 + 1/3*m2
1/3*m2 = m1 - 1/3*m1
1/3*m2 = 2/3*m1
m2 = 2m1
From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.
To learn more about inelastic collision visit:
brainly.com/question/14521843
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