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Viktor [21]
3 years ago
15

Which statement best explains why an object appears green in sunlight?

Physics
2 answers:
Lesechka [4]3 years ago
5 0

Answer:

D

Explanation:

More green light is reflected while more red and blue light is absorbed.

Helen [10]3 years ago
3 0

Answer:

This question is incomplete, the options are:

A) The object absorbs most white light and refracts most green light.

B) The object refracts most white light and absorbs most green light.

C) More green light is absorbed while more red and blue light is reflected.

D) More green light is reflected while more red and blue light is absorbed.

The answer is D.

Explanation:

Light is an electromagnetic wave that contains different colours at different wavelength. The colour of light that is seen depends on the wavelength of light that is REFLECTED, while other wavelengths of light are ABSORBED. This feature is dependent on the properties of each object that received the sunlight.

For example, an object will appear GREEN because it has properties that enables it to REFLECT most of the GREEN LIGHT but absorbs most of the RED AND BLUE LIGHT in the sunlight passing through the object.

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What equation can be used to solve for acceleration
Tanya [424]

Answer: acceleration can be calculated when a known force is acting on an object of known mass. Newton’s law can be represented by the equation F net = m x a, where F net is the total force acting on the object, m is the object’s mass, and a is the acceleration of the object.

Explanation:

3 0
3 years ago
The maximum displacement of an oscillatory motion is A=0.49m. Determine the position x at which the kinetic energy of the partic
Tatiana [17]

Answer:

The position x, is ± 0.4 m.

Explanation:

The total mechanical energy of the oscillatory motion is given as;

E_T = U +K.E\\\\E_T = \frac{1}{2} kA^2\\\\ \frac{1}{2} kA^2 = U +K.E\\\\K.E = \frac{1}{2} kA^2 - U ----equation(1)

When the kinetic energy (E) is half of the elastic potential energy (U);

K.E = \frac{U}{2} ----equation(2)

Equate (1) and (2)

\frac{U}{2} = \frac{1}{2} kA^2 - U\\\\U = kA^2 -2U\\\\U+2U = kA^2\\\\3 U =  kA^2\\\\3(\frac{1}{2} kx^2) = kA^2\\\\\frac{3}{2} x^2=A^2\\\\x^2 = \frac{2}{3} A^2\\\\x = \sqrt{\frac{2}{3} A^2} \\\\x = A\sqrt{\frac{2}{3} } \\\\x = 0.49\sqrt{\frac{2}{3} }\\\\x = + /- (0.4 \ m)

Thus, the position x, is ± 0.4 m.

8 0
3 years ago
lace each example of a collision in correct category. bumper cars colliding man jumping in a cab mud sticking to car hat being s
Marrrta [24]

Answer:

bumper cars colliding- inelastic

man jumping in a cab- perfectly inelastic

mud sticking to car - perfectly inelastic

hat being sat on door being slammed- inelastic

ball bouncing- elastic

Explanation:

In a perfectly inelastic collision, the objects stick together after collision and move with a common velocity. Maximum kinetic energy is lost during such collision.

For an inelastic collision, kinetic energy is partly lost and the colliding objects move apart at different velocities. This is often encountered in real life situations.

For an elastic collision, both momentum and kinetic energy are conserved. The object rebounds with the same relative velocity with which it approached.

3 0
4 years ago
What is an electromagnet
dusya [7]

Answer:

An electromagnet is a magnet that runs on electricity. Unlike a permanent magnet, the strength of an electromagnet can easily be changed by changing the amount of electric current that flows through it. The poles of an electromagnet can even be reversed by reversing the flow of electricity.

8 0
3 years ago
Air is compressed in a cylinder such that the volume changes from 100.0 to 10.0 in^3. The initial pressure is 50.0 psia and the
EleoNora [17]

Answer:

5953.42 J

Explanation:

Given:

Initial volume, V_i= 100 in³

Final Volume, V_f = 10 in³

Initial pressure = 50 psia

Temperature = 100° F = 310.93 K

For isothermal reversible process, work done is given as:

Work done = -2.303RTlog_{10}\frac{V_f}{V_i}

Where,

R is the ideal gas constant = 8.314 J/mol.K

or

Work done = -2.303\times8.314\times310.93log_{10}\frac{10}{100}

or

Work done = 5953.42 J

7 0
3 years ago
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