Now the vertical velocity of the ball thrown at an angle 10° is given as
Voy(initial vertical velocity)= 30m/s x sin 10
Voy(initial vertical velocity)= 5.2m/s
Now the ball is decelerating with an acceleration due to gravity equivalent to 9.8m/s^2.
Let Vy be the final velocity and that is equal to zero in this case.
Now
Vy= Voy- tx9.8
Where t is the time at which the vertical velocity becomes 0.
Substituting the values we get
0= 5.2-tx9.8
9.8t=5.2
t=0.53 secs
Answer:
Average speed = 1.2 m/s
Average velocity = 0.4 m/s
Explanation:
Average speed = total distance/total time
Average speed = (40 + 20)/(40 + 10)
Average speed = 60/50
Average speed = 1.2 m/s
Average velocity = displacement/time
Now, she ran 40 m south and ran 20 m back north which is in the direction of where she began the journey.
Thus;
Displacement = 40 - 20 = 20 m
Average velocity = 20/50 = 0.4 m/s
It expands and pushes the crack further aprt
Answer:
The correct answer is;
The magnitude of the force is 35.12 N
Explanation:
To solve the question, we note that the friction is zero and the force causes motion of a stationary mass
One of the equations of motion is required such as
v² = u² + 2× a× s
Where
v = Final velocity = 5.93 m/s
u = Initial velocity = 0 m/s , object at rest
a = acceleration
s = distance moved = 32 meters
But v = Distance/Time = 32 m /5.4 s = 5.93 m/s
Therefore
5.93² = 2×a×32
or a = 35.12/ 64 = 0.55 m/s²
Therefore Force F = Mass m × Acceleration a
Where mass m = 64 kg
Therefore F = 64 kg×0.55 m/s² = 35.12 N
