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Paraphin [41]
1 year ago
10

Glucose solution is administered to a patient in a hospital. The density of the solution is 1.308 kg/l. If the blood pressure in

the vein is 35.7 mmHg, then what is the minimum necessary height of the IV bag above the position of the needle?
Physics
1 answer:
Helga [31]1 year ago
4 0

The minimum necessary height of the IV bag above the position of the needle is 0.37 m.

<h3>Minimum necessary height</h3>

The minimum necessary height of the IV bag above the position of the needle is calculated as follows;

P = ρgh

where;

  • ρ is density = 1.308 kg/L = 1308 kg/m³
  • g is acceleration due to gravity = 9.8 m/s²
  • p is pressure = 35.7 mmHg = 4759.609 Pa
  • h is height, (m) = ?

Substitute the given parameters and solve for minimum height

h = P/ρg

h = (4759.609) / (9.8 x 1308)

h = 0.37 m

Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.

Learn more about pressure here: brainly.com/question/25736513

#SPJ1

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2 years ago
A ball is thrown directly downward with an initial speed of 7.70 m/s, from a height of 30.2 m. After what time interval does it
KatRina [158]

Answer:

t = 1.82

Explanation:

Given

u = 7.70m/s -- initial velocity

s = 30.2m --- height

Required

Determine the time to hit the ground

This will be solved using the following motion equation.

s = ut + \frac{1}{2}gt^2

Where

g = 9,8m/s^2

So, we have:

30.2 = 7.70t + \frac{1}{2} * 9.8 * t^2

30.2 = 7.70t + 4.9 * t^2

Subtract 30.2 from both sides

30.2 -30.2  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9t^2 - 30.2

7.70t + 4.9t^2 - 30.2  = 0

4.9t^2 + 7.70t - 30.2  = 0

Solve using quadratic formula:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = 4.9;\ b = 7.70;\ c = -30.2

t = \frac{-7.70\±\sqrt{7.70^2 - 4*4.9*-30.2}}{2*4.9}

t = \frac{-7.70\±\sqrt{651.21}}{9.8}

t = \frac{-7.70\±25.52}{9.8}

Split the expression

t = \frac{-7.70+25.52}{9.8} or t = \frac{-7.70-25.52}{9.8}

t = \frac{17.82}{9.8} or t = -\frac{33.22}{9.8}

Time can't be negative;  So, we have:

t = \frac{17.82}{9.8}

t = 1.82

Hence, the time to hit the ground is 1.82 seconds

7 0
2 years ago
Bro i need help omg.
sergey [27]

Answer:

25.

Explanation:

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Answer:

Given

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Form

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The output voltage of a power supply is normally distributed with mean 5 V and standard deviation 0.02 V. If the lower and upper
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A

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P(4.95

P(4.95

P(4.95

P(4.95

P(4.95

Hence probability that a power supply selected at random will conform to the specifications on voltage is 0.9876

8 0
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