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hram777 [196]
3 years ago
10

What is the mass of a football in free fall with a total force due to gravity of 782N?

Physics
2 answers:
Alla [95]3 years ago
8 0

P = 782 N

g = 9.81 m/s^2

So:

m = P/g = 782N/9.81 m/s^2 = 79,7 Kg

Mama L [17]3 years ago
4 0

5

Explanation:

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A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
4 years ago
A band director instructs students to play a pitch louder. How will the sound wave change when the band plays the same pitch lou
ZanzabumX [31]

Answer:

The amplitude of the sound wave will increase.

Explanation:

3 0
4 years ago
Read 2 more answers
A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radi
andreev551 [17]

Answer:2

Explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim r=20 cm

mass of rim m=2 kg

Angular momentum \vec{L}=I\cdot \vec{\omega }

I=mr^2=2\times 0.2^2=0.08 kg-m^2

\omega =\frac{v}{r}=\frac{5}{0.2}=25 rad/s

L=0.08\times 25=2kg-m^2/s  

direction of Angular momentum will be towards west

7 0
3 years ago
For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N, where t is in seconds. If
KATRIN_1 [288]

Answer:

15.6m/s

Completed Question;

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5

Explanation:

Mass m = 2500kg

Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s

To determine speed v2;

Using the principle of momentum and impulse;

mv1 + ∫₀⁵ F dt = mv2

8 0
3 years ago
A cell has an emf of 1.5 V and an internal resistance of 0.65 Q.
weeeeeb [17]

Answer:

14000 J / 0.40 J/s = 35 000 s or about 9.75 hrs

5 0
3 years ago
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