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masya89 [10]
3 years ago
13

The force of friction between an object and the surface upon which it is sliding is 14N and the coefficient of friction between

them is 0.72. What is the weight of the object? ​
Physics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

14 x 0.27 = 3.78 is your answer

Explanation:

the question is asking for the weight of the object so you multiply and get 3.79

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What is the formula for calculating acceleration​
Komok [63]

Answer:

the formula for calculating acceleration is ending speed minus starting speed divided by time.

7 0
3 years ago
If gravity did not affect the pain of a horizontally thrown ball the ball would
Drupady [299]

If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it. 

That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\

If you threw the ball horizontally, then it would keep moving in the
same direction you threw it.  But don't forget:  The Earth is not flat.
The Earth is a sphere.  So, as the ball kept going farther and farther
in the same straight line, the Earth would curve away from it, and it
would look like the ball is getting farther and farther from the ground.
 
4 0
3 years ago
Read 2 more answers
a 4.60 kg mass is placed on top of a vertical spring, which compresses a distance of 2.31 cm. calculate the force constant (in n
Lerok [7]

The restoring force of the spring cancels the weight of the mass, so by Newton's second law

∑ F = F[spring] - mg = 0   ⇒   F[spring] ≈ 45.1 N

where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,

F[spring] = k x

where x = 0.0231 m. Then the spring constant is

k = F[spring]/x ≈ 1950 N/m

4 0
2 years ago
If the mass of an object is 14 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?
mixas84 [53]

Using the formula:

w = m x g ....... eq1

here w is weight of the object.

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 14 lbm (given)

acceleration of gravity, g= 32.0 ft/s^{2}

Now, substituting the values in equation (1):

w = 14lbm x 32.0 ft/s^{2} = 448 lbm ft/s^{2}

since, 1 lbf = 32.174 lbm ft/s^{2}

so, w = 448 x \frac{1}{32.174}

w = 13.924lbf

Hence, the mass of an object is 13.924 lbf.

To know more about such questions, visit:

brainly.com/question/10936674

#SPJ4

3 0
2 years ago
A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.
lozanna [386]
You can find

1) time to hit the ground
2) initial velocity
3) speed when it hits the ground

Equations

Vx = Vxo

x = Vx * t

Vy = Vyo + gt

Vyo = 0

Vy = gt

y = yo - Vyo - gt^2 / 2

=> yo - y = gt^2 / 2

1) time to hit the ground

=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2

=> t = √1.631 s^2 = 1.28 s

2) initial velocity

Vxo = x / t = 6.5m / 1.28s = 5.08 m/s

3) speed when it  hits the ground

Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s

V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2

=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
7 0
3 years ago
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