Answer:
c) marketing and selling products that use ore materials
The right half will be a new bar magnet of 2cm with north pole on the right side and south pole on teh left.
They both make a thing go faster and slower but the relationship is force.
Answer:
the rate of acceleration of the train is 4 m/s²
Explanation:
Given;
initial velocity of the train, u = 10 m/s
change in time of motion, dt = 5 s
final velocity of the train, v = 30 m/s
The rate of acceleration of the train is calculated as;
![a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bv-u%7D%7Bdt%7D%20%3D%20%5Cfrac%7B30-10%7D%7B5%7D%20%3D%20%5Cfrac%7B20%7D%7B5%7D%20%3D%204%20%5C%20m%2Fs%5E2)
Therefore, the rate of acceleration of the train is 4 m/s²