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3 years ago

We have discovered some exoplanets that are still forming from a nebula. How might those planets change over time?

1 answer:

6 0

Based on several theories made by scientists, planets are formed because of the accumulation of gases and other particles that are attracted to each other. These accumulated gases form into clumps and eventually the clumps get bigger and turn into a big orbital mass. The exoplanets may experience change over time through the observance of its orbit in a particular axis, and if there are other debris that might affect the planet's continuous growth.

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Tara's cell phone plan costs $39.00 a month, which includes 100 text messages. After she uses all of her text messages, it will

vekshin1

I think it is $585.hope it is right

5 0

3 years ago

If we assume that the metallic plates are perfect conductors, the electric field in their interiors must vanish. given that the

Svetlanka [38]

here the charge density of metal plate is given as

$charge density = \sigma$

now the electric field is given Gauss law

$\int E. dA = \frac{q}{\epsilon_0}$

now here E = constant

so we will have

$E. \int dA = \frac{q}{\epsilon_0}$

Since total area on both sides of plate will be double and becomes 2A

$E. 2A = \frac{q}{\epsilon_0}$

$E = \frac{q/A}{2\epsilon_0}$

$E = \frac{\sigma}{2\epsilon_0}$

Now if we will find the electric field inside the metal plate

Then as we know that total charge inside the plate will always be zero

so we have

$E = 0$

7 0

3 years ago

A ball, with a mass of 5.9kg, is thrown directly upwards. It reaches a maximum height of 10m from the point at which it was rele

katrin2010 [14]

Answer:

14 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, when the ball is thrown from the ground, it has only kinetic energy, which is given by

$K=\frac{1}{2}mv^2$

where m = 5.9 kg is the mass of the ball and v is its initial speed.

As the ball goes up, its speed decreases, so its kinetic energy decreases and converts into gravitational potential energy. When the ball reaches its maximum height, the speed has become zero, and all the kinetic energy has been converted into gravitational potential energy, given by:

$U=mgh$

where g = 9.8 m/s^2 is the gravitational acceleration and h = 10 m is the maximum height reached by the ball.

Since we can ignore air resistance, energy must be conserved, so the initial kinetic energy must be equal to the final potential energy of the ball, so we can write:

$K=U\\\frac{1}{2}mv^2=mgh$

And we can solve the equation to find v, the initial speed of the ball:

$v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(10 m)}=14 m/s$

8 0

2 years ago

Which of the following are true? Select all that apply. The net electric field at any location inside a block of copper is zero

Agata [3.3K]

Answer:

1) The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.

2) In equilibrium, there is no net flow of mobile charged particles inside a conductor.

3) If the net electric field at a particular location inside a piece of metal is not zero, the metal is not in equilibrium.

Explanation:

1) and 3) A block of copper is a conductor. The charged particles on a conductor in equilibrium are at rest, so the intensity of the electric field at all interior points of the conductor is zero, otherwise, the charges would move resulting in an electric current.

2) The charged particles on a conductor in equilibrium are at rest.

6 0

3 years ago

This is the si unit of current

skelet666 [1.2K]

Answer:

ampere

and it is denoted by A

3 0

2 years ago

Read 2 more answers