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jeyben [28]
3 years ago
8

We have discovered some exoplanets that are still forming from a nebula. How might those planets change over time?

Physics
1 answer:
Rudik [331]3 years ago
6 0
Based on several theories made by scientists, planets are formed because of the accumulation of gases and other particles that are attracted to each other. These accumulated gases form into clumps and eventually the clumps get bigger and turn into a big orbital mass. The exoplanets may experience change over time through the observance of its orbit in a particular axis, and if there are other debris that might affect the planet's continuous growth.
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A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?
denpristay [2]

Answer:

1275J

Explanation:

Given parameters:

Force on box  = 85N

Distance moved  = 15m

Unknown:

Work done  = ?

Solution:

Work done is the amount of force applied on a body to move it through a specific distance.

 Work done  = Force x distance

Now insert the parameters and solve;

 Work done = 85 x 15  = 1275J

4 0
3 years ago
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What do odometer and speedometer read ?
maksim [4K]
Odometer: tells you the distance traveled by vehicle since it was new (or when last reset)

Speedometer: tells you the velocity of the vehicle at that moment.
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3 years ago
Can an element be a molecule
Serga [27]

an element can make a molecule. so technically yes.

6 0
3 years ago
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The intensity at distance from a spherically symmetric sound source is 100 W/m2. What is the intensity at five times this distan
ss7ja [257]

To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.

Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is

I = \frac{P}{A}

The area of a sphere is given by

A = 4\pi r^2

So replacing we have to

I = \frac{P}{4\pi r^2}

Since the question tells us to find the proportion when

r_1 = 5r_2 \rightarrow \frac{r_2}{r_1} = \frac{1}{5}

So considering the two intensities we have to

I_1 = \frac{P_1}{4\pi r_1^2}

I_2 = \frac{P_2}{4\pi r_2^2}

The ratio between the two intensities would be

\frac{I_1}{I_2} = \frac{ \frac{P_1}{4\pi r_1^2}}{\frac{P_2}{4\pi r_2^2}}

The power does not change therefore it remains constant, which allows summarizing the expression to

\frac{I_1}{I_2}=(\frac{r_2}{r_1})^2

Re-arrange to find I_2

I_2 = I_1 (\frac{r_1}{r_2})^2

I_2 = 100*(\frac{1}{5})^2

I_2 = 4W/m^2

Therefore the intensity at five times this distance from the source is 4W/m^2

3 0
3 years ago
A 900 N student runs up the stairs 3.5 m high in 12<br> seconds. How much POWER do they generate?
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Answer:

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