Answer:
894 deg K
Explanation:
The computation is shown below:
Given that
V1 denotes the initial volume of gas = 2.00 L
T1 denotes the initial temperature of gas = 25 + 273 = 298 K
V2 denotes the final volume of gas = 6.00 L
T2 = ?
Based on the above information
Here we assume that the pressure is remain constant,
So,
V1 ÷ T1 = V2 ÷ T2
T2 = T1 × V2 ÷ V1
= (298)(6) ÷ (2)
= 894 deg K
Answer:
![T_{2,H_2O}=89^oC](https://tex.z-dn.net/?f=T_%7B2%2CH_2O%7D%3D89%5EoC)
Explanation:
Hello,
In this case, we notice that the energy gained by the first sample of water is lost by the second sample of water as they are heated and cooled respectively, therefore, in terms of heats:
![Q_{1,H_2O}=-Q_{2,H_2O}](https://tex.z-dn.net/?f=Q_%7B1%2CH_2O%7D%3D-Q_%7B2%2CH_2O%7D)
Which in terms of masses, heat capacities and temperatures is:
![m_{1,H_2O}*Cp_{1,H_2O}*(T_{EQ}-T_{1,H_2O})=-m_{2,H_2O}*Cp_{2,H_2O}*(T_{EQ}-T_{2,H_2O})](https://tex.z-dn.net/?f=m_%7B1%2CH_2O%7D%2ACp_%7B1%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B1%2CH_2O%7D%29%3D-m_%7B2%2CH_2O%7D%2ACp_%7B2%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B2%2CH_2O%7D%29)
In such a way, as the heat capacity is the same and the initial temperature of the cold water is required, we solve for it via:
![m_{1,H_2O}*(T_{EQ}-T_{1,H_2O})=-m_{2,H_2O}*(T_{EQ}-T_{2,H_2O})\\T_{EQ}-T_{2,H_2O}=\frac{m_{1,H_2O}*(T_{EQ}-T_{1,H_2O})}{-m_{2,H_2O}} \\\\T_{2,H_2O}=T_{EQ}+\frac{m_{1,H_2O}*(T_{EQ}-T_{1,H_2O})}{m_{2,H_2O}}](https://tex.z-dn.net/?f=m_%7B1%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B1%2CH_2O%7D%29%3D-m_%7B2%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B2%2CH_2O%7D%29%5C%5CT_%7BEQ%7D-T_%7B2%2CH_2O%7D%3D%5Cfrac%7Bm_%7B1%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B1%2CH_2O%7D%29%7D%7B-m_%7B2%2CH_2O%7D%7D%20%5C%5C%5C%5CT_%7B2%2CH_2O%7D%3DT_%7BEQ%7D%2B%5Cfrac%7Bm_%7B1%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B1%2CH_2O%7D%29%7D%7Bm_%7B2%2CH_2O%7D%7D)
With the given data we obtain:
![T_{2,H_2O}=T_{EQ}+\frac{m_{1,H_2O}*(T_{EQ}-T_{1,H_2O})}{m_{2,H_2O}}\\\\T_{2,H_2O}=48.9^oC+\frac{102g*(48.9^oC-22.6^oC)}{66.9g} =48.9^oC+40.1^oC\\T_{2,H_2O}=89^oC](https://tex.z-dn.net/?f=T_%7B2%2CH_2O%7D%3DT_%7BEQ%7D%2B%5Cfrac%7Bm_%7B1%2CH_2O%7D%2A%28T_%7BEQ%7D-T_%7B1%2CH_2O%7D%29%7D%7Bm_%7B2%2CH_2O%7D%7D%5C%5C%5C%5CT_%7B2%2CH_2O%7D%3D48.9%5EoC%2B%5Cfrac%7B102g%2A%2848.9%5EoC-22.6%5EoC%29%7D%7B66.9g%7D%20%3D48.9%5EoC%2B40.1%5EoC%5C%5CT_%7B2%2CH_2O%7D%3D89%5EoC)
Which means the second sample was hot.
Regards.
Hey there!!!
The correct answer is A. peripheral membrane.
Hope this helps you and have a great day!!!! I wish you the best of luck (:
Answer:
Heating a substance increases the speed at which molecules move.
Explanation:
<span>H2SO3 I DONT REALLY KNOW HOW TO EXPLAIN IT BUT HERE IS THE ANSWER
-BATMAN FOREVER!!!!
</span>