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Anna71 [15]
3 years ago
14

What is the main difference between the Schrödinger model and the Bohr atomic model?

Chemistry
2 answers:
dexar [7]3 years ago
9 0

Answer:

Bohr believed electron orbits were circular, but Schrödinger’s equations represent complex shapes describing the probable locations of electrons.

Explanation:

Nuetrik [128]3 years ago
3 0

The key difference is that in (most modern interpretations of) the Schrodinger model the electron of a one-electron atom, rather than traveling in fixed orbits about the nucleus, has a probablity distribution permitting the electron to be at almost all locations in space, some being much more likely than others

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Convert 1663.5 g to mg
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Answer:

It will be 1663500mg

Explanation:

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What are the four types of biological molecules and their main function in the human body?
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Answer:

There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids)

Explanation:

There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids), and each is an important component of the cell and performs a wide array of functions. ... Biological macromolecules are organic, meaning that they contain carbon.

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Which of the following describes the bond between nitrogen atoms in an N, molecule? (1) 2 electrons are shared (2) 4 electrons a
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Explanation:

(3) 6 electrons are shared.

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what is magnesium? why does your body need it? how much do you need (per day)? What happens if you have too much or too little o
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8 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
2 years ago
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