B Longitude
Explanation:
The line of longitude or longitude does not affects climates.
Climate is the weather condition over a place for a long period of time. It usually takes several years to delineate the climate of an area.
- Longitude is the distance on the earth surface that runs form east to west.
- All lines of longitude are all great circles.
- Latitude are lines from north to south on the earth surface. Only the equator is a great circle.
- Latitude affects climate. In fact based on the division of lines of latitude on can predict climatic patterns on earth.
- Proximity to water bodies also affects climatic condition because of the effect of land and sea breeze and other climatic factors.
- Elevation affects climate a whole lot. Physiography of a place determines the weather to a very large extent.
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Answer:
(a).The speed of the water in the nozzle is 3.014 m/s.
(b). The pressure in the nozzle is 1.86 atm.
Explanation:
Given that,
Nozzle diameter = 0.25 in = 0.00635 m
Hose pipe diameter = 0.64 in = 0.016256 m
Pressure = 1.9 atm =192518 Pa
(a). We need to calculate the speed of the water in the nozzle
Flow Speed at the inlet pipe will be given by using Continuity Equation



Where, A = area of pipe


Put the value into the formula


The speed of the water in the nozzle is 3.014 m/s.
(b). We need to calculate the pressure in the nozzle
Using Bernoulli's Theorem,

Where, 


Put the value into the formula



Hence, (a).The speed of the water in the nozzle is 3.014 m/s.
(b). The pressure in the nozzle is 1.86 atm.
Answer:
Common Examples of Imagery
Taste: The familiar tang of his grandmother's cranberry sauce reminded him of his youth. Sound: The concert was so loud that her ears rang for days afterward. Sight: The sunset was the most gorgeous they'd ever seen; the clouds were edged with pink and gold.
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Answer:
a) K = 0.63 J, b) h = 0.153 m
Explanation:
a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is
w² =
where d is the distance from the pivot point to the center of mass and I is the moment of inertia.
The rod is a homogeneous body so its center of mass is at the geometric center of the rod.
d = L / 2
the moment of inertia of the rod is the moment of a rod supported at one end
I = ⅓ m L²
we substitute
w =
w =
w =
w = 4.427 rad / s
an oscillatory system is described by the expression
θ = θ₀ cos (wt + Φ)
the angular velocity is
w = dθ /dt
w = - θ₀ w sin (wt + Ф)
In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1
In the exercise it is indicated that at the lowest point the angular velocity is
w = 4.0 rad / s
the kinetic energy is
K = ½ I w²
K = ½ (⅓ m L²) w²
K = 1/6 m L² w²
K = 1/6 0.42 0.75² 4.0²
K = 0.63 J
b) for this part let's use conservation of energy
starting point. Lowest point
Em₀ = K = ½ I w²
final point. Highest point
Em_f = U = m g h
energy is conserved
Em₀ = Em_f
½ I w² = m g h
½ (⅓ m L²) w² = m g h
h = 1/6 L² w² / g
h = 1/6 0.75² 4.0² / 9.8
h = 0.153 m
For the sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
<h3>What is effect of density of a medium on wavelength of a wave?</h3>
The density of a medium is directly proportional to the wavelength of a wave.
The higher the density of the medium, the longer the wavelength of a wave.
Therefore, for a sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
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