parallel-plate air capacitor is made from two plates 0.070 m square, spaced 6.3 mm apart. What must the potential difference bet
1 answer:
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Answer:
(a).The speed of the water in the nozzle is 3.014 m/s.
(b). The pressure in the nozzle is 1.86 atm.
Explanation:
Given that,
Nozzle diameter = 0.25 in = 0.00635 m
Hose pipe diameter = 0.64 in = 0.016256 m
Pressure = 1.9 atm =192518 Pa
(a). We need to calculate the speed of the water in the nozzle
Flow Speed at the inlet pipe will be given by using Continuity Equation
Where, A = area of pipe
Put the value into the formula
The speed of the water in the nozzle is 3.014 m/s.
(b). We need to calculate the pressure in the nozzle
Using Bernoulli's Theorem,
Where,
Put the value into the formula
Hence, (a).The speed of the water in the nozzle is 3.014 m/s.
(b). The pressure in the nozzle is 1.86 atm.
Answer:
a) K = 0.63 J, b) h = 0.153 m
Explanation:
a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is
w² =
where d is the distance from the pivot point to the center of mass and I is the moment of inertia.
The rod is a homogeneous body so its center of mass is at the geometric center of the rod.
d = L / 2
the moment of inertia of the rod is the moment of a rod supported at one end
I = ⅓ m L²
we substitute
w =
w =
w =
w = 4.427 rad / s
an oscillatory system is described by the expression
θ = θ₀ cos (wt + Φ)
the angular velocity is
w = dθ /dt
w = - θ₀ w sin (wt + Ф)
In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1
In the exercise it is indicated that at the lowest point the angular velocity is
w = 4.0 rad / s
the kinetic energy is
K = ½ I w²
K = ½ (⅓ m L²) w²
K = 1/6 m L² w²
K = 1/6 0.42 0.75² 4.0²
K = 0.63 J
b) for this part let's use conservation of energy
starting point. Lowest point
Em₀ = K = ½ I w²
final point. Highest point
Em_f = U = m g h
energy is conserved
Em₀ = Em_f
½ I w² = m g h
½ (⅓ m L²) w² = m g h
h = 1/6 L² w² / g
h = 1/6 0.75² 4.0² / 9.8
h = 0.153 m