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AleksAgata [21]

3 years ago

10

What happens when a larger force is applied?

1 answer:

tatyana61 [14]3 years ago

7 0

When the applied force is larger than the maximum force of static friction the object will move. ... The magnitude of the kinetic friction is: fk=μkN. Remember that static friction is present when the object is not moving and kinetic friction while the object is moving.

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3 years ago

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3 years ago

A condenser accepts steam from the turbine in problem 2 at a pressure of 2.34 kPa. Saturated water at the same pressure leaves t

vaieri [72.5K]

Answer:

The answer is "83.98, 1889.195, and 1889.195"

Explanation:

Given value:

$\bold{P_{4}=2.34 \ kPa}$

In point a:

The value of $h_{f4}=83.915 \ \ \frac{Kj}{kg}\\$

$V_4=0.001002 \ \ \frac{Kj}{kg}\\\\U_4= 83.98 \ \ \frac{Kj}{kg}\\\\$

In point b:

calculating heat leaves formula= $h_3-h_{f4}$

$= 1973.11-83.915\\\\= 1889.195 \ \ \frac{KJ}{kg}$

In point c:

calculating Heat transfer rate formula $=m(h_3-h_4)$

$= 1(1889.195)\\\\ = 1889.19 \ \ kw.$

7 0

3 years ago

A capillary tube is immersed vertically in a water container. Knowing that water starts to evaporate when the pressure drops bel

Anuta_ua [19.1K]

Answer:

$d=0.414\times 10^{-4}\ m$

Explanation:

Given that

P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water = $1000\ kg/m^3$

So the capillarity rise h

$h=\dfrac{\Delta P}{\rho g}$

$h=\dfrac{100\times 1000-4\times 1000}{1000\times 10}$

h= 9.61 m

We know that for capillarity rise h

$h=\dfrac{2\sigma cos\theta }{r\rho g}$

$r=\dfrac{2\sigma cos\theta }{h\rho g}$

$r=\dfrac{2\times 1 cos4^{\circ} }{9.61\times 1000\times 10}$

$r=0.207\times 10^{-4}\ m$

$d=0.414\times 10^{-4}\ m$

3 0

3 years ago

4.A compression spring has a diameter of 0.67 in and a coil diameter of 0.067 in, with 30 total coils. The spring is to be made

Akimi4 [234]

Answer:

Fatigue factor of safety is 2.0267

Explanation:

Solution is attached below.

4 0

4 years ago