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liraira [26]
3 years ago
9

PDC Bank is working on creating an AI application that enables customers to send SMS to the AI application to allow banking acti

vities from their registered ID. Jane, the project engineer, has taken bank customer data from the last few years from the server and is using it to train the ML to recognize and authenticate actual users and to ensure unauthorized users are barred from entering the application. Suppose the AI application has been compromised, and the reason has been identified as compromised data being used to improve the ML accuracy. What kind of attack is the PDC Bank application subjected to?
Engineering
1 answer:
bogdanovich [222]3 years ago
5 0

The kind of attack that the PDC Bank application is subjected to due to compromised data is: Adversarial artificial intelligence

Adversarial artificial intelligence is a form of attack on a neural network where a wrong algorithm is entered into the system to deceive the end user.

The aim of this machine learning method is to deceive the end user.

This is what happens to the PDC Bank when its data was compromised in the course of improving the machine learning accuracy.

Learn more about Adversarial artificial intelligence here:

brainly.com/question/22190244

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For the amount of heat rejected:

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= 110 + 22 = 132KJ

[tex[ q_H = \frac{Q_L}{m} [/tex];

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Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c

Convert 69.5°c to K we have 342.5K

To find the minimum temperature:

T_L = \frac{T_H}{1.2};

T_L = \frac{342.5}{1.2}

= 285.4K

Convert to °C we have 12.4°C

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Air in a piston-cylinder assembly is compressed isentropically from state 1, where T1 = 35°C, to state 2, where the specific vol
ivanzaharov [21]

Answer:

(a) T₂ =747.5 and K= 474.5 °C (b) 330.178 kJ/kg

Explanation:

Solution

T₁ = 35°C = 308

the first step to take is to Use the Table A-17: Ideal gas  properties for air:

Now,

At T₁ = 308 K

V₁ = 217.67 + [308-305/310-305] (221.25 -217.67)

So,

V₁ =219.818 kJ/kg

Thus,

Vr₁ = 596 + [308-305/310-305] (572.3 - 596)

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Vr₂/Vr₁ = 1/10

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Applying Table A-17, at Vr₂ = 58.178

Then,

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V₂ =544.02 + [58.178 - 59.82/57.63 -59.82] (551.99 - 544.02)

so,

V₂ =549.996 kJ/kg

Hence,

(b) q - w = v₂ -v₁

= 0 -w  = 549.996- 219.818

w = 330.178 kJ/kg

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3 years ago
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