P2 = 54.6 kPa
Explanation:
Given:
V1 = 10.0 L. V2 = 50.0 L
P1 = 273 kPa. P2 = ?
We can use Boyle's law to solve this problem.
P1V1 = P2V2
Solving for P2,
P2 = (V1/V2)P1
= (10.0 L/50.0 L)(273 kPa)
= 54.6 kPa
average atomic mass of Cu = 63.54
Explanation:
average atomic mass = atomic mass of isotope 1 × abundance of isotope 1 + atomic mass of isotope 2 × abundance of isotope 2 +...+ atomic mass of isotope n × abundance of isotope n
average atomic mass of Cu = atomic mass of Cu-63 × abundance of isotope Cu-63 + atomic mass of isotope Cu-65 × abundance of isotope Cu-65
average atomic mass of Cu = 62.93 × (69.17 / 100) + 64.93 × (30.83 / 100)
average atomic mass of Cu = 63.54
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Answer: approximately 15.1 grams.
Explanation: The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want. Change 25 grams of potassium chlorate to moles. Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron. 1 K x 39 grams/mole+1 Cl x 35.4grams/ mole+3 O x 16 grams/ mole = 122.4 grams / mole Potassium Chlorate 25 122.4 = moles. 2.05 moles of Potassium Chlorate. There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride. 2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride. Find the gram molecular mass of Potassium Chloride. 1 K x 39 = 39+1 Cl x 35.4 = 35.4 = 74.4 grams / mole. 2.05 moles x 74.4 grams/ mole = 15.2 grams
Answer:
Explanation:
The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:
Subsituting and computing:
It simply equals 4x-16.......
the expression is in lowest terms, so you can’t do anything else