<span>68g since 34/100 is 34 right?
so if you have 200g of H2O you can put in twice as much KCl
so it is 68g</span>
Answer:
3.37kg of NaCl is the salt content of the dead sea
Explanation:
A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.
To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:
<em>Volume in milliliters:</em>
10.0L * (1000mL / 1L) = 10000mL
<em>Mass of NaCl:</em>
10000mL * (33.7g NaCl / 100mL) = 3370g NaCl
<em>In kg:</em>
3370g * (1kg / 1000g) =
<h3>3.37kg of NaCl is the salt content of the dead sea</h3>
Answer:
2.51 g
Explanation:
The mass of 1 mol of iron is 55.84 g.
For 0.0450 mol,

Answer: The temperature of the gas is 132.25K and -140.75°C
Explanation:
Given that:
Volume of helium gas (V) = 18.5L
Temperature of helium gas (T) = ?
Pressure (P) = 0.85 atm
Number of moles (n) = 1.45 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T
15.725 atm•L = 0.1189 atm•L•K-1 x T
T = 15.725 atm•L / 0.1189 atm•L•K-1
T = 132.25K
Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273
So, T(in Celsius) = 132.25K - 273
= -140.75°C
Thus, the temperature of the gas is 132.25K and -140.75°C