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Kazeer [188]
3 years ago
14

You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m

from the release point of the ball. How long does the ball take to reach the wall?
Show Options
A.11.15 s
B.11.5 s
C.1.115 s
D.1.15 s
Physics
2 answers:
Genrish500 [490]3 years ago
7 0

Answer:

D.1.15 s

Explanation:

When we decompose the velocity into two perpendicular components, the total vector and its components form a right triangle. Therefore, these components will be given by:

cos\theta=\frac{v_x}{v}\\v_x=vcos\theta(1)\\sin\theta=\frac{v_y}{v}\\v_y=vsin\theta

Using (1), we calculate the horizontal speed of the ball:

v_x=25\frac{m}{s}cos(40^\circ)\\v_x=19.15\frac{m}{s}

Recall thatv=\frac{x}{t}, solving for t:

t=\frac{x}{v}\\t=\frac{22m}{19.15\frac{m}{s}}\\t=1.15s

kirza4 [7]3 years ago
3 0
The horizontal speed is going to be the cosine of the given speed, therefore, the horizontal speed is 19.15 m/s. To find the time, divide the 22 m distance by the velocity. This results in 1.131 seconds, which is in between C and D.
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From this diagram which of the following can you conclude
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8 0
2 years ago
The electric field of a sinusoidal electromagnetic wave obeys the equation E = (375V /m) cos[(1.99× 107rad/m)x + (5.97 × 1015rad
kenny6666 [7]

Answer:

a)  v = 2,9992 10⁸ m / s , b)  Eo = 375 V / m ,  B = 1.25 10⁻⁶ T,

c)     λ = 3,157 10⁻⁷ m,   f = 9.50 10¹⁴ Hz ,  T = 1.05 10⁻¹⁵ s , UV

Explanation:

In this problem they give us the equation of the traveling wave

        E = 375 cos [1.99 10⁷ x + 5.97 10¹⁵ t]

a) what the wave velocity

all waves must meet

        v = λ f

In this case, because of an electromagnetic wave, the speed must be the speed of light.

        k = 2π / λ

        λ = 2π / k

        λ = 2π / 1.99 10⁷

        λ = 3,157 10⁻⁷ m

        w = 2π f

        f = w / 2 π

        f = 5.97 10¹⁵ / 2π

        f = 9.50 10¹⁴ Hz

the wave speed is

        v = 3,157 10⁻⁷   9.50 10¹⁴

        v = 2,9992 10⁸ m / s

b) The electric field is

           Eo = 375 V / m

to find the magnetic field we use

           E / B = c

           B = E / c

            B = 375 / 2,9992 10⁸

            B = 1.25 10⁻⁶ T

c) The period is

           T = 1 / f

            T = 1 / 9.50 10¹⁴

            T = 1.05 10⁻¹⁵ s

the wavelength value is

          λ = 3,157 10-7 m (109 nm / 1m) = 315.7 nm

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