2 years ago

An airplane whose air speed is 527 mi/hr covers a distance of 907 miles in 2.25 hrs. How strong was the head wind against it?

Physics

1 answer:

melamori03 [73]2 years ago

6 0

Answer:

cda

Explanation:

csa

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Answer:

$EMF = 5.01 \times 10^{-4} Volts$

Explanation:

Here we know that the EMF induced in this Field is given as

$EMF = vBL$

here B = perpendicular component of magnetic field

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now we have

$B = 5\times 10^{-5} sin40$

$v = 13 m/s$

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now we have

$EMF = (13)(3.21 \times 10^{-5})(1.2)$

$EMF = 5.01 \times 10^{-4} Volts$

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