Answer:
0,07448M of phosphate buffer
Explanation:
sodium monohydrogenphosphate (Na₂HP) and sodium dihydrogenphosphate (NaH₂P) react with HCl thus:
Na₂HP + HCl ⇄ NaH₂P + NaCl <em>(1)</em>
NaH₂P + HCl ⇄ H₃P + NaCl <em>(2)</em>
The first endpoint is due the reaction (1), When all phosphate buffer is as NaH₂P form, begins the second reaction. That means that the second endpoint is due the total concentration of phosphate that is obtained thus:
0,01862L of HCl×
= 1,862x10⁻³moles of HCl ≡ moles of phosphate buffer.
The concentration is:
= <em>0,07448M of phosphate buffer</em>
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I hope it helps!
It has to be noted that sodium is an element which belongs in the first column of the periodic table. This means that it has a valence electron of 1 which further means that it is capable of donating one of its electron to another element during reaction. This is exactly the explanation as to why it becomes charged +1 after the reaction.
Answer:
co+ o2+ 2co2 is not balanced reaction
Dipole-induced dipole forces.
In contrast to C2H5OH, which is a very polar molecule, bromine is non-polar and has zero dipole moment. Charges are separated within polar molecules.
When a nonpolar Br2 molecule interacts with a polar C2H5OH molecule, one half of the bromine molecule acquires a charge and the other half acquires an opposing charge. A dipole is created when two adjacent bromine molecules have different charges. Bromine molecules must thus overcome the intermolecular forces—also known as dipole-induced dipole forces—that form in order to dissolve in ethanol.
Find more on bromine at : brainly.com/question/865727
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Answer:
B
Explanation:
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