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3 years ago

How many electrons are in the third energy level? 2 8 18 20

Physics

2 answers:

Alisiya [41]3 years ago

7 0

Answer:

Explanation:

plz mark brainlyest

Blababa [14]3 years ago

6 0

Answer:

B)8

Explanation:

In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.

Hope this helps, have a nice day! (^-^)

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A beam of light of wavelength lambda = 541nm is normally incident on a diffraction grating which has 600 lines m * m ^ - 1 Deter

MrMuchimi

Answer:

Angle of diffraction for second order maxima is θ = 18.941°

Explanation:

From the question it is given that

wavelength of incident light = λ = 541 nm = 541 x $10^-^9 m$

order of maxima = n =2

diffraction grating has 600 lines per mm

⇒ distance between two slit is $\frac{1mm}{600}$ = 1.66 x $10^-^6$ m

using the relation of Braggs diffraction formula i.e.,

2dsinθ = nλ ..................................(1)

where, d = distance between two lines of grating

θ is the angle of diffraction

n= order of maxima

λ is the intensity of incident photon

on substituting the respected values in relation (1) we get,

2 x 1.66 x $10^-^6$ m sinθ = 2 x 541 x $10^-^9 m$

⇒ sinθ = 0.3246

⇒ θ = $sin^-^1(0.3246)$ = 18.941 °

8 0

3 years ago

A student has a displacement of 304 m north in 180 s. What was the student's average velocity?

DanielleElmas [232]

Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

$v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s$

Hence, the student's average velocity is 1.69 m/s.

6 0

4 years ago

A stone is tied to a string and whirled at constant speed in a horizontal circle. The speed is then doubled without changing the

Tanya [424]

Answer:

Afterward the magnitude of the acceleration of the stone is four times as great

Explanation:

A stone tied to a string and whirled at a constant speed in a horizontal circle will have a centripetal acceleration given by

$a = \frac{v^{2} }{r}$

Where $a$ is the centripetal acceleration

$v$ is the speed

and $r$ is the radius of the circle

Here, the radius of the circle is the length of the string.

Now, from the question

The speed is then doubled without changing the length of the string,

Let the new speed be $v_{2}$ , that is

$v_{2} = 2v$

and without changing the length of the string means radius $r$ is constant.

To determine the magnitude of the acceleration of the stone afterwards,

Let the new acceleration be $a_{2}$ .

Then we can write that

$a_{2} = \frac{v_{2}^{2} }{r}$

From

$a = \frac{v^{2} }{r}$

$v = \sqrt{ar}$

Recall that

$v_{2} = 2v$

∴ $v_{2} = 2\sqrt{ar}$

Now, we will put the value of $v_{2}$ into

$a_{2} = \frac{v_{2}^{2} }{r}$

Then,

$a_{2} = \frac{(2\sqrt{ar}) ^{2} }{r}$

$a_{2} = \frac{4ar }{r}$

$a_{2} = 4a$

The new magnitude of the acceleration of the stone is four times the initial acceleration.

Hence,

Afterward the magnitude of the acceleration of the stone is four times as great

3 0

3 years ago

Hydrogen is found as a gas on Earth but exists in all four states in the solar

Viefleur [7K]

Answer: the sample of solid has less energy than the sample of gas

Explanation:

APEX

5 0

3 years ago

During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed

krok68 [10]

Answer:

Detailed solution is given below:

3 0

3 years ago