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3 years ago

How many electrons are in the third energy level? 2 8 18 20

Physics

2 answers:

Alisiya [41]3 years ago

7 0

Answer:

Explanation:

plz mark brainlyest

Blababa [14]3 years ago

6 0

Answer:

B)8

Explanation:

In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.

Hope this helps, have a nice day! (^-^)

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Gravity is not considered matter. <br>A. True <br>B. False

Strike441 [17]

Answer:

false gravity is not considered matter

7 0

3 years ago

The body is subjected to a force of 0,4 N m with a shoulder of 5 cm. What is the magnitude of this force?

igor_vitrenko [27]

Answer:

Explanation:

the body is subjected to pressure equals to force force inverse to the area of that body given that it is in motion

5 0

3 years ago

How fast does a 3 kg rocket accelerate if a force of 140 N is applied?

elixir [45]

<h3>Answer:</h3>

46.67 m/s²

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of a rocket = 3 kg
Force applied = 140 N

we are supposed to calculate the acceleration of the rocket;

We are going to use the second Newton's law of motion;
According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

= 140 N ÷ 3 kg

= 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

3 0

4 years ago

.A 0.2-kg aluminum plate, initially at 20°C, slides down a 15-m-long surface, inclined at a 30 angle to the horizontal. The forc

Ainat [17]

To solve this problem, it is necessary to apply the concepts related to Work according to the Force and distance, as well as the concepts related to energy lost-or gained-by heat. Mathematically the energy corresponding to heat is given as:

$Q = mC_p(\Delta T)$

Where,

m = mass

$C_p$ = Specific heat

$\Delta T$ = Change in Temperature

At the same time the Work made by the Force and the distance is given as:

$W = F*d \rightarrow W=mg*d$

As the force is applied at an angle of 30 degrees, the efficient component would be given by the vertical then the work / energy would be determined as:

$W = mg*dsin(30)$