Answer:
Explanation:
It is given that,
Mass of bundle of shingles, m = 10 kg
Upward acceleration of the shingles, 
The radius of the motor of the pulley, r = 0.17 m
Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :
T = 113 N
Let 
is the minimum torque that the motor must be able to provide. It is given by :
So, the minimum value of torque is 19.21 N-m. Hence, this is the required solution.
Answer:
B. silicate rocks and metals
Answer:
Ex(P) = -3.602 x 10^6 N/C
Explanation:
- q2 = 2.6 μC = the net charge on the conducting shell
- inner radius of conducting shell = a = 2.2 cm =0.022m
- outer radius of conducting shell = b = 4.5 cm = 0.045m
1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;
Ex(P) = k(q1+q2)/r^2
= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2
Ex(P) = -27.9 x 10^3/ 0.007744
Ex(P) = -3.602 x 10^6 N/C
As we know,
so, let's solve for velocity (v)
Answer:
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
Explanation:
The impedance of a series circuit is
Z₀² = R² + (X_L-X_C) ²
when we place another resistor in series the initial resistance impedance changes to
Z² = (R + R₂) ² + (X_L - X_C) ²
let's analyze this expression
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
