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Bas_tet [7]
3 years ago
7

How would the freezing point of seawater compare with that of pure water? a)higher b) lower c) the same d) ten times higher

Chemistry
2 answers:
melamori03 [73]3 years ago
4 0
The answer would be B) Lower, because pure water freezes at 32 degrees Fahrenheit whereas salt water freezes at 28.4 degrees Fahrenheit. Hopefully this helps!
olga_2 [115]3 years ago
3 0

Answer:

Freezing point of seawater is lower as compared to pure water

Explanation:

Seawater contains salts like MgCl_{2}, NaCl etc.

According to colligative properties of molecules, presence of solute in a pure solvent lowers freezing point of pure solvent obeying the following equation-

                                        \Delta T_{f}=k_{f}.m

where \Delta T_{f} is lowering of freezing point, k_{f} if cryogenoscopic constant of solvent and m is molality of solution.

In seawater, water is the solvent and MgCl_{2}, NaCl etc are solutes.

Hece freezing point of seawater is lower than pure water

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If 100cm3 of O2 diffused in 4s and 50cm3 of gas Y diffused in 3s. calculate the relative molecular mass of gas X (O=16).
sertanlavr [38]

Answer:

T2/T=√M1√M2

T2=3 T1=4 M1=O2=32

M2=?

4/2=√M2/√32

=1.3

Explanation:

8 0
3 years ago
I have no idea how to do this and need help
den301095 [7]

Answer:

60.55%

Explanation:

nO3=155/48

nO2 used: 3/2nO3=4.84375

percent yield: 4.84375/8=60.55%

5 0
3 years ago
Water can be formed in the following reaction:
andreev551 [17]

Answer is: 10 moles of water will be produced.

Balanced chemical reaction of formation of water:

2H₂ + O₂ → 2H₂O.

n(H₂) = 10 mol; amount of hydrogen gas.

From balanced chemical reaction: n(H₂) : n(H₂O) = 2 : 2 (1 : 1).

n(H₂O) = n(H₂).

n(H₂O) = 10 mol; amount of water.

6 0
3 years ago
ILL MARK BRAINLIEST :)
DanielleElmas [232]

Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

Mass of Na = 23 g/mol

Mass of Cl = 35.5 g/mol

Sum of mass of reactants = mass of Na + mass of Cl

= 23 + 35.5 g/mol

= 58.5 g/mol

Mass of product formed is as follows.

Mass of NaCl = mass of Na + mass of Cl

= (23 g/mol + 35.5) g/mol

= 58.5 g/mol

As mass reacted is equal to the amount of mass formed. This shows that mass is conserved.

As a result, law of conservation of mass is obeyed.

3 0
3 years ago
If you need to measure the volume of liquid in a bottle of eye drops, what unit would be the most practical?
aniked [119]
The volume of eye drop fluid in a bottle is specified in milliliter, because in medical 1 drop=12ml
7 0
3 years ago
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