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3 years ago

How would the freezing point of seawater compare with that of pure water? a)higher b) lower c) the same d) ten times higher

2 answers:

4 0

The answer would be B) Lower, because pure water freezes at 32 degrees Fahrenheit whereas salt water freezes at 28.4 degrees Fahrenheit. Hopefully this helps!

olga_2 [115]3 years ago

3 0

Answer:

Freezing point of seawater is lower as compared to pure water

Explanation:

Seawater contains salts like $MgCl_{2}$ , NaCl etc.

According to colligative properties of molecules, presence of solute in a pure solvent lowers freezing point of pure solvent obeying the following equation-

$\Delta T_{f}=k_{f}.m$

where $\Delta T_{f}$ is lowering of freezing point, $k_{f}$ if cryogenoscopic constant of solvent and m is molality of solution.

In seawater, water is the solvent and $MgCl_{2}$ , NaCl etc are solutes.

Hece freezing point of seawater is lower than pure water

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vlabodo [156]

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3 years ago

Which sample of matter is classified as a solution

svet-max [94.6K]

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3 years ago

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Anastasy [175]

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3 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

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3 years ago

An atom with a high metallic character usually has a ____ electron affinity and a ____ atomic radius.

lianna [129]

Low electron affinity and large atomic radius

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Electron affinity increases from left to right within a period. This is caused by the decrease in atomic radius. Electron affinity decreases from top to bottom within a group. This is caused by the increase in atomic radius.

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3 years ago