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Bas_tet [7]
3 years ago
7

How would the freezing point of seawater compare with that of pure water? a)higher b) lower c) the same d) ten times higher

Chemistry
2 answers:
melamori03 [73]3 years ago
4 0
The answer would be B) Lower, because pure water freezes at 32 degrees Fahrenheit whereas salt water freezes at 28.4 degrees Fahrenheit. Hopefully this helps!
olga_2 [115]3 years ago
3 0

Answer:

Freezing point of seawater is lower as compared to pure water

Explanation:

Seawater contains salts like MgCl_{2}, NaCl etc.

According to colligative properties of molecules, presence of solute in a pure solvent lowers freezing point of pure solvent obeying the following equation-

                                        \Delta T_{f}=k_{f}.m

where \Delta T_{f} is lowering of freezing point, k_{f} if cryogenoscopic constant of solvent and m is molality of solution.

In seawater, water is the solvent and MgCl_{2}, NaCl etc are solutes.

Hece freezing point of seawater is lower than pure water

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JulsSmile [24]

The correct answer of gibbs free energy is -232 KJ.

ΔG = -nFE° = -2*96485*1.20 = -232 (kJ)

The Gibbs free energy of a system at any point in time is defined as its enthalpy minus the product of its temperature times its entropy. Because it is defined in terms of thermodynamic properties that are state functions, the system's Gibbs free energy is a state function. It is commonly referred to as free energy because it is readily available at all times. If necessary, the reaction can steal this energy without having to pay or work for it. The reaction between sodium chloride and water is regarded as spontaneous, and it has a negative G. When solid NaCl is immersed in water, it begins to dissociate on its own without any external assistance.

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8 0
1 year ago
Read the following chemical equations.
lora16 [44]

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻  ⇒2K⁺O⁻²H⁺ + I₂⁰

Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

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8 0
3 years ago
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jeyben [28]

Answer:

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7 0
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Type the correct answer in the box. Express your answer to three significant figures. Calcium nitrate reacts with sodium phospha
RoseWind [281]

6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

W = 0.0196mole × 310g/mole = 6.07 grams

Hence, 6.07 grams is the theoretical yield of calcium phosphate.

To know more about moles, visit the below link:

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7 0
2 years ago
Write a word equation for the chemical reaction.<br><br> I’ll brainlist.
Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

Hope it helps.. if yes, plz mark me as brainliest

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