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LenaWriter [7]
4 years ago
10

What is sedentary lifestyle?

Physics
1 answer:
Effectus [21]4 years ago
7 0
A sedentary lifestyle is when you don't make any exercise. For example, if I spent a whole week just sitting down answering questions, that would be an example of a sedentary lifestyle, because I'm not running or jogging. Having that type of lifestyle can make you fat and get health problems.

Have a nice day! :)
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If you add a light bulb to the circuit, the filament in the bulb will resist the flow of
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Light and heat!

Explanation:

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An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the
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We have that the density of the fluid is

\rho_f=178.57  kg/m3

From the question we are told that

object of volume 0.0004m^3

density 6000kg/m^3

fluid of density 5000kg/m^3.

Force F=0.7N

Generally the equation for the Force   is mathematically given as

F= v*\rho_f*g\\\\0.7= 0.0004*\rho_f*9.8\\\\\rho_f=\frac{0.7}{0.0004*9.8}

\rho_f=178.57  kg/m3

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8 0
3 years ago
Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1.4 kW/m2. (a) Assuming that Earth (and
baherus [9]

To solve the problem we will require the concept of Force as a definition of pressure and Area, and the concept of light pressure itself determined by the relationship between intensity and the speed at which light travels. We will match the terms and find the desired force value,

F = PA

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P = Pressure

A = Area

Pressure due to the light of the sun will be

P= \frac{I}{c}

Here,

I = Intensity

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Equation both therms we have that

F = \frac{IA}{c}

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F = \frac{I(\pi r^2)}{c}

Replacing with our values (Adding the radius of the Earth)

F = \frac{(1.4*10^3W/m^2)(\pi (6.32*10^6m)^2)}{3.0*10^8m/s}

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3 years ago
Pre-Test
SSSSS [86.1K]

Answer:

the atom cannot be divided into smaller particles

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What is the gauge pressure (in atm) in a 25.0°C car tire containing 3.81 mol of gas in a 31.5 L volume? (Enter your answer to at
bagirrra123 [75]

Answer:

Explanation:

Given

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Volume of gas V=31.5\ L\approx 31.5\times 10^{-3}\ m^3

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Using Ideal gas Equation to find the Pressure of gas

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P=299.66\ kPa

And we know Atmospheric Pressure is 101.325\ kPa

Therefore Gauge pressure is given by

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P=198.34\ kPa

4 0
3 years ago
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