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2 years ago

What are the examples of Inertia of motion

Physics

1 answer:

Drupady [299]2 years ago

3 0

Seat belts tighten in a car when it stops quickly.

Men in space find it more difficult to stop moving because of a lack of gravity acting against them.

When playing football, a player is tackled, and his head hits the ground.

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HOPE IT'S HELPFUL FOR U MATE

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Solve each problem. Be sure to show your work and give a final answer with units rounded to the given number of significant figu

Alex Ar [27]

Answer:

1. the voltage will be 2.35×12.5 = 29.4V

2. the resistance would be 9.0/6.2= 1.45ohms

3. in series they will add up thus 4+8+12= 24ohms

4. in parallel it will be 2.18ohms

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3 years ago

What is the acceleration if we speed up from 10m/s to 30 m/s in 10 seconds

lina2011 [118]

Acceleration= change in speed/ change in time

30-10= 20 (change in speed)
Time= 10 seconds

20/10= 2
Acceleration= 2 m/s^2

Hope this helps! :)

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3 years ago

You apply the same amount of heat to 5 grams of water and 5 grams of aluminum. The temperature of the aluminum increases more th

LiRa [457]

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3 years ago

A 1000-kg car has 50,000 joules of kinetic energy. What is the speed?

djyliett [7]

K.E = 1/2mv^2

The kinetic energy is 50,000 J and the mass of the car is 10,000 kg.

50,000 J = 1/2(10,000kg)v^2
Solve for v (velocity)
50,000 J = 5,000 kg x v^2
10 = v^2
$\sqrt{10} = v$
about 3 m/s (in terms of significant figures)

4 0

3 years ago

Read 2 more answers

There is a plate with moment of inertia Ip = 0.0711 kgm2 , rotating around its center of mass with angular speed of 4.53 rad/s.

Anna007 [38]

Answer:

1) their common angular speed = 3.038 rad/s

2) kinetic energy loss = 0.24J

Explanation:

1) This is a case of conservation of angular momentum.

The initial angular momentum must be equal to the final angular momentum

Initial angular momentum = I x w

Where I = moment of inertia, and

w = angular momentum.

Initial angular momentum = 0.0711 x 4.53 = 0.322 kg-m2-rad/s

After addition of ring, moment of inertia becomes,

0.0711 + 0.0353 = 0.106 kg-m2

Therefore, final angular momentum will be

0.106 x Wf

Where Wf = final common angular velocity

Equating the two angular momentum we have

0.322 = 0.106Wf

Wf = 0.322/0.106 = 3.038 rad/s

2) KE = 1/2 x I x w^2

Initial KE = 1/2 x 0.0711 x 4.53^2

= 0.729 J

Final KE = 1/2 x 0.106 x 3.038^2

= 0.489 J

Loss in KE = 0.729 - 0.489 = 0.24 J

5 0

3 years ago

What are the examples of Inertia of motion​

What are the examples of Inertia of motion