<span>Each atom contains an equal number of protons and electrons; these particles will be equal in value to an element's atomic number</span>
Answer:
The angular velocity is
5.64rad/s
Explanation:
This problem bothers on curvilinear motion
The angular velocity is defined as the rate of change of angular displacement it is expressed in rad/s
We know that the velocity v is given as
v= ωr
Where ω is the angular velocity
r is 300mm to meter = 0.3m
the radius of the circle
described by the level
v=1.64m/s
Making ω subject of the formula and solving we have
ω=v/r
ω=1.64/0.3
ω=5.46 rad/s
Refer to the diagram shown below.
The following discussion assumes a simplistic analysis that ignores air resistance and variations in the terrain that the missile travels over.
Let the launch velocity be V₀ at an angle of θ relative to the horizontal.
The horizontal component of velocity is V₀ cosθ.
If the time of flight is

, then

where r = the range of the missile.
Also, the time, t, when the missile is at ground level is given by

where g = acceleration due to gravity.
t = 0 corresponds to when the missile is launched. Therefore

Therefore

Typically, θ=45° to achieve maximum range, so that

This analysis is more applicable to a scud missile rather than a powered, guided missile.
Answer:

Usually, θ=45°