3 years ago

What is the freezing point of copper

Physics

1 answer:

gayaneshka [121]3 years ago

6 0

The freezing point of copper is 1984 degrees F and 1085 degrees C

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A horse is grazing for food. It trots rightward 15 m to eat a carrot, then walks rightward 20 m, to another carrot, then turns l

mafiozo [28]

Answer:

Explanation:

Velocity = Displacement/time

Displacement of the horse is the distance covered in a specified direction

Total distance of the horse towards the right = 15m + 20m = 35m

Total distance of the horse towards the left = 4m

Displacement = Distance towards the right - Distance towards the left

Displacement = 35m-4m

Displacement = 31m

Time taken = 74seconds

substitute the values gotten into the velocity formula

average velocity = 31m/74s

average velocity = 0.42m/s

Hence the magnitude of its average velocity is 0.42s

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4 years ago

L'intensité de la pesanteur g à la surface d'une planète peut se calculer par la formule : g=G. M R^ 2 M;\\ R: masse de la planè

jarptica [38.1K]

Answer:

Step-by-step explanation:

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2 years ago

a girl pushes a cart to the left a 100-N force. a boy pushes it to the right with a 50-N force. The net force exerted on the car

AURORKA [14]

Since the net force is the amount of force favoring the side with the most force acted upon it,

100 - 50 = 50

50N to the left

Hope this helps!

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4 years ago

A capacitor is made by taking two sheets of aluminum foil, each 0.022 mm thick and placing between them a sheet of paper which c

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3 years ago

Light of wavelength 645 nm is incident on a double slit. The angle between the central bright fringe and the second dark fringe

kumpel [21]

Answer:

Slit separation, $d=1.13\times 10^{-5}\ m$

Explanation:

It is given that,

Wavelength of light, $\lambda=645\ nm=645\times 10^{-9}\ m$

The angle between the central bright fringe and the second dark fringe, $\theta=4.9^{\circ}$

In case of double slits, the condition for dark fringe is given by :

$d\ sin\theta=(n-\dfrac{1}{2})\lambda$

n = 2

$d\ sin\theta=\dfrac{3}{2}\lambda$

$d=\dfrac{3\lambda}{2\ sin\theta}$

$d=\dfrac{3\times 645\times 10^{-9}}{2\ sin(4.9)}$

$d=1.13\times 10^{-5}\ m$

So, the slit separation is $1.13\times 10^{-5}\ m$ . Hence, this is the required solution.

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3 years ago