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choli [55]
3 years ago
15

What is the freezing point of copper

Physics
1 answer:
gayaneshka [121]3 years ago
6 0
The freezing point of copper is 1984 degrees F and 1085 degrees C 
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What equals the number of protons in an atom
Reptile [31]

<span>Each atom contains an equal number of protons and electrons; these particles will be equal in value to an element's atomic number</span>

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3 years ago
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Rotation of the lever OA is controlled by the motion of the contacting circular disk of radius r = 300 mm whose center is given
sergiy2304 [10]

Answer:

The angular velocity is

5.64rad/s

Explanation:

This problem bothers on curvilinear motion

The angular velocity is defined as the rate of change of angular displacement it is expressed in rad/s

We know that the velocity v is given as

v= ωr

Where ω is the angular velocity

r is 300mm to meter = 0.3m

the radius of the circle

described by the level

v=1.64m/s

Making ω subject of the formula and solving we have

ω=v/r

ω=1.64/0.3

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3 years ago
an airplane traveling 245 m/s east expericences turbulence, so the pilot slows down to 230 m/s. it takes the pilot 7 seconds to
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a=v-u/t

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a=2

8 0
3 years ago
Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?
bogdanovich [222]

Answer:

6 m/sec

Explanation:

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7 0
4 years ago
For anti-ballistic missile system, the time of flight tf is determined by the initial speed v0 of the missile and the maximum ra
umka2103 [35]
Refer to the diagram shown below.

The following discussion assumes a simplistic analysis that ignores air resistance and variations in the terrain that the missile travels over.

Let the launch velocity be V₀ at an angle of θ relative to the horizontal.
The horizontal component of velocity is V₀ cosθ.
If the time of flight is t_{f}, then
r=V_{o} \, t_{f}
where r = the range of the missile.

Also, the time, t, when the missile is at ground level is given by
0=V_{o} sin\theta \, t- \frac{1}{2}gt^{2}
where g = acceleration due to gravity.

t = 0 corresponds to when the missile is launched. Therefore
t_{f} =  \frac{2V_{o}sin\theta}{g}

Therefore
r= \frac{2V_{o}^{2} sin\theta cos\theta}{g} = \frac{V_{o}^{2} sin(2\theta)}{g}

Typically, θ=45° to achieve maximum range, so that
r= \frac{V_{o}^{2}}{g}

This analysis is more applicable to a scud missile rather than a powered, guided missile.

Answer:
t_{f} =  \frac{r}{V_{o} cos\theta} \\\\ r= \frac{V_{o}^{2} sin(2\theta)}{g}
Usually, θ=45°

6 0
3 years ago
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