Answer:

Explanation:
When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.
So:
24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O
The next step is to divide each mass by their molar mass to convert your grams to moles.
24.42/40.08 = 0.6092 mol
17.07/14.01 = 1.218 mol
58.85/15.99 = 3.680 mol
Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.
0.6092 mol/0.6092 mol = 1
1.218 mol/0.6092 mol = 2
3.680 mol/0.6092 mol = 6
So the empirical formula is 
Answer:
It's Effective Collision.
Explanation:
Hope my answer has helped you!
This reaction is known as
Wittig Reaction. A powerful reaction for the synthesis of
Alkene. In question the starting materials are
aldehyde and a Phosphorous
Ylide. Ylide when reacted with aldehyde produces a four membered ring which on
rearrangement gives Alkene and triphenylphosphine oxide. Phosphorous having great
affinity toward the oxygen is the driving force of this rearrangement. The reaction along with product (highlighted
blue) is as follow,
60 g C2H6 × 1 mol C2H6 x 7 mol O2 x 32 g O2 = ~223.5 g O2
30.068 g 2 mol C2H6 1 mol O2