NEED HELP ASAP

list the following from greatest to least mass: 1 mol of H2, 2 moles of K, 3 moles of Mg, and 4 moles of He

Leya [2.2K]

H₂ = 2 g/mol

1 x 2 = 2 g of H₂
________________________

K = 39.09 g/mol

2 x 39.09 = 78.18 g of K
________________________________

Mg = 24.3 g/mol

3 x 24.3 = 72.9 g of Mg
_________________________________

He = 4 g/mol

4 x 4 = 16 g of He
___________________________________

Order : K , Mg , He and H₂

hope this helps!

3 0

3 years ago

04.05 mol

victus00 [196]

Answer:

34.8 g

Explanation:

Answer:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 123.90 70.91 208.24

P₄ + 20Cl₂ ⟶ 4PCl₅

Mass/g: 46.0 32.0

2. Calculate the moles of each reactant

$\text{moles of P}_{4} = \text{46.0 g P}_{4} \times \dfrac{\text{1 mol P}_{4}}{\text{123.90 g P}_{4}} = \text{0.3713 mol P}_{4}\\\\\text{moles of Cl}_{2} = \text{32.0 g Cl }_{2} \times \dfrac{\text{1 mol Cl }_{2}}{\text{70.91 g Cl }_{2}} = \text{0.4513 mol Cl }_{2}$

3. Calculate the moles of PCl₅ we can obtain from each reactant

From P₄:

The molar ratio is 4 mol PCl₅:4 mol P₄

$\text{Moles of PCl}_{5} = \text{0.3713 mol P}_{4} \times \dfrac{\text{4 mol PCl}_{5}}{\text{4 mol P}_{4}} = \text{0.3713 mol PCl}_{5}$

From Cl₂:

The molar ratio is 4 mol PCl₅:20 mol Cl₂

$\text{Moles of PCl}_{5} = \text{0.4513 mol Cl}_{2}\times \dfrac{\text{4 mol PCl}_{5}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol PCl}_{5}$

4. Identify the limiting and excess reactants

The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.

The excess reactant is phosphorus.

5. Mass of excess reactant

(a) Moles of P₄ reacted

The molar ratio is 1 mol P₄:20 mol Cl₂

$\text{Moles reacted} = \text{0.4513 mol Cl}_{2} \times \dfrac{\text{4 mol P}_{4}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol P}_{4}$

(b) Mass of P₄ reacted

$\text{Mass reacted} = \text{0.090 26 mol P}_{4} \times \dfrac{\text{123.90 g P}_{4}}{\text{1 mol P}_{4}} = \text{11.18 g P}_{4}$

(c) Mass of P₄ remaining

Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄

4 0

3 years ago

The purpose of a functional group is to increase the reactivity of a carbon chain. Another term for functionality is Question 7

lions [1.4K]

Explanation:

option A)oxidation is my answer

7 0

3 years ago

Which of the following is usually done last in the scientific method of investigation?

djverab [1.8K]

C - Analyze data and draw conclusions. After an experiment or in this case; an investigation, you would analyze your data that you collected from the investigation/experiment, and draw conclusions based on your data.

3 0

4 years ago

Read 2 more answers

List the levels of the Mohs hardness scale – For EACH level, tell the characteristics found in minerals on that level and give 1

choli [55]

$HEY THERE!!$

QUESTION:- List the levels of the Mohs hardness scale -

ANSWER:-
Mohs Hardness Scale kit containing:-
(1) talc
(2) gypsum
(3) calcite
(4) fluorite
(5) apatite
(6) orthoclase
(7) quartz
(8) topaz
(9) corundum
(10) diamond.

HOPE IT HELPS YOU.

5 0

3 years ago