Answer:
Endothermic.
Explanation:
Because the temperature decreased, the reaction is endothermic.
Endothermic reactions absorb heat from the surroundings. In this case, the dissolution of the ammonium nitrate absorbed heat from the surroundings (the water). Hence, the temperature of the solution decreased.
To answer this item, we must take note that the ligand that binds the tightest is the one with the lowest dissociation constant, Kd. Kd's for both A and B are already given so, we only need to solve Kds for C and D.
Kd of C
0.3 = (1x10⁻⁶)/(1x10⁻⁶ + Kd) ; Kd = 2.3x10⁻⁶
Kd of D
0.8 = (1x10⁻⁹)/(1x10⁻⁹ + Kd) ; Kd = 2.5x10⁻10
Since Ligand D has the least value of dissociation constant then, it can be concluded that it binds the tightest.
Answer:
2 KOH → H₂O + K₂O
Explanation:
When KOH descomposes in potassium oxide, K₂O and water, H₂O.
The unbalanced equation is:
KOH → H₂O + K₂O
As you can see, 2 hydrogen, potassium and oxygen atoms are produced, to balance this equation we can write:
2 KOH → H₂O + K₂O
This is the balanced equation because 2 atoms of K, H and O are in reactants and products