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RSB [31]
3 years ago
9

How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? Show

all steps of your calculation as well as the final answer. HCl + Ca(OH) 2 → H2O + CaCl2
Chemistry
1 answer:
kow [346]3 years ago
3 0
We first balance the equation. It will now become:
2HCl + Ca(OH)₂ ⇒ 2H₂O + CaCl₂

We also calculate the molar mass of H₂O:
2 x H = 1 g x 2 = 2g
O = 16 g
molar mass of H₂O = 18 g/mol

Then using dimensional analysis:
73.7 mL H₂O x (0.987 g H₂O/1 mL H₂O) x (1 mol H₂O/18 g H₂O)
x (1 mol Ca(OH)₂/2 mol H₂O) 

= 2.02 mol Ca(OH)₂
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25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are
geniusboy [140]

The new concentrations of HClO and NaClO are  0.25M and 19M

Calculation of number of moles of each component,

Molarity of HClO = number of moles/volume in lit =  0. 500 M

Number of moles = molarity  of HClO× volume in lit = 0. 500 M× 0.025 L

Number of moles of HClO = 0.0125 mole

Molarity of NaClO  = number of moles/volume in lit =  0. 38 M

Number of moles = molarity of NaClO × volume in lit = 0. 38 M× 0.025 L

Number of moles of  NaClO  = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of HClO = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of HClO = 0.25M

Molarity of NaClO  = number of moles/volume in lit = 0.95mole/0.05L

Molarity of NaClO  = 19 M

learn about  Molarity

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2 years ago
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asambeis [7]

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